Surveying If θ and δ be the latitude of an observer and declination of a heavenly body respectively, the upper culmination of the body will be south of zenith if its zenith distance, is δ - θ ½ (θ - δ) θ - δ θ + δ δ - θ ½ (θ - δ) θ - δ θ + δ ANSWER DOWNLOAD EXAMIANS APP
Surveying If ‘δ’ is the declination of the Polaris and ‘λ’ is the latitude of the place, the azimuth of the Polaris, is sin (90° - δ)/sin (90° - λ) cos (90° - δ)/cos (90° - λ) tan (90° + δ)/tan (90° + λ) cos δ/cos λ sin (90° - δ)/sin (90° - λ) cos (90° - δ)/cos (90° - λ) tan (90° + δ)/tan (90° + λ) cos δ/cos λ ANSWER DOWNLOAD EXAMIANS APP
Surveying The declination and right ascension of the sun becomes 23° 27' N and 90° respectively on September 21 March 21 December 22 June 21 September 21 March 21 December 22 June 21 ANSWER DOWNLOAD EXAMIANS APP
Surveying The difference of levels between two stations A and B is to be determined. For best results, the instrument station should be equidistant from A and B as far as possible from the line AB closer to the higher station closer to the lower station equidistant from A and B as far as possible from the line AB closer to the higher station closer to the lower station ANSWER DOWNLOAD EXAMIANS APP
Surveying The necessary geometrical condition for triangulation adjustment is: The sum of the three angles of a plane triangle should be 180° The sum of the eight angles of a braced quadrilateral should be 360° The sum of the angles around a station should be 360° All listed here The sum of the three angles of a plane triangle should be 180° The sum of the eight angles of a braced quadrilateral should be 360° The sum of the angles around a station should be 360° All listed here ANSWER DOWNLOAD EXAMIANS APP
Surveying If a star whose declination is 60° N culminates at zenith, its altitude at the lower culmination, is 30° 40° 20° 10° 30° 40° 20° 10° ANSWER DOWNLOAD EXAMIANS APP
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