Surveying If θ and δ be the latitude of an observer and declination of a heavenly body respectively, the upper culmination of the body will be south of zenith if its zenith distance, is ½ (θ - δ) δ - θ θ - δ θ + δ ½ (θ - δ) δ - θ θ - δ θ + δ ANSWER DOWNLOAD EXAMIANS APP
Surveying If the altitudes of a star at its upper and lower transits are 60° 30' and 19° 30' respectively, the latitude of the place, is 30° 45° 60° 35° 30° 45° 60° 35° ANSWER DOWNLOAD EXAMIANS APP
Surveying The point on the celestial sphere vertically below the observer's position, is called Zenith Pole Celestial point Nadir Zenith Pole Celestial point Nadir ANSWER DOWNLOAD EXAMIANS APP
Surveying Homologous points are Plumb points of stereo pair of photographs Nodal points of the camera lens Corresponding points on the ground and photograph Opposite corners of a photograph Plumb points of stereo pair of photographs Nodal points of the camera lens Corresponding points on the ground and photograph Opposite corners of a photograph ANSWER DOWNLOAD EXAMIANS APP
Surveying In the cross-section method of indirect contouring, the spacing of cross-sections depends uponi) contour intervalii) scale of planiii) characteristics of groundThe correct answer is (i), (ii) and (iii) (i) and (ii) (ii) and (iii) only (i) (i), (ii) and (iii) (i) and (ii) (ii) and (iii) only (i) ANSWER DOWNLOAD EXAMIANS APP
Surveying If ‘δ’ is the declination of the star and ‘φ’ is the latitude of the observer then the hour angle of the star at elongation is given by tan H = tan φ . cot δ sin H = tan φ . cot δ cos H = tan φ . cot δ None of these tan H = tan φ . cot δ sin H = tan φ . cot δ cos H = tan φ . cot δ None of these ANSWER DOWNLOAD EXAMIANS APP
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