Surveying If the equatorial distance between two meridians is 100 km, their distance at 60° latitude will be 800 km 600 km 500 km 1000 km 800 km 600 km 500 km 1000 km ANSWER DOWNLOAD EXAMIANS APP
Surveying The nautical mile is the length of 1 degree of latitude 1 minute of longitude 1 minute of latitude 1 degree of longitude 1 degree of latitude 1 minute of longitude 1 minute of latitude 1 degree of longitude ANSWER DOWNLOAD EXAMIANS APP
Surveying In observations of equal precision, the most probable values of the observed quantities are those that render the sum of the squares of the residual errors a minimum, is the fundamental principle of Gauss' Mid Latitude formula D'Alembert's method Least square method Legendre's method Gauss' Mid Latitude formula D'Alembert's method Least square method Legendre's method ANSWER DOWNLOAD EXAMIANS APP
Surveying The position of a heavenly body on the celestial sphere can be completely specified by Its declination and hour angle Its declination and right ascension Its altitude and azimuth All listed here Its declination and hour angle Its declination and right ascension Its altitude and azimuth All listed here ANSWER DOWNLOAD EXAMIANS APP
Surveying Pick up the incorrect statement from the following. The angular distance of heavenly bodies on observer's meridian measured from the pole, is Polar distance Co-declination Co-altitude Co-latitude Polar distance Co-declination Co-altitude Co-latitude ANSWER DOWNLOAD EXAMIANS APP
Surveying With standard meridian as 82° 30' E the standard time at longitude 90° E is 8 h 30 m. The local mean time at the place will be 9 h 00 m 7 h 00 m 8 h 00 m 7 h 30 m 9 h 00 m 7 h 00 m 8 h 00 m 7 h 30 m ANSWER DOWNLOAD EXAMIANS APP
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