Machine Design Lewis form factor for 14½° composite and full depth involute system is (where T = Number of teeth) 0.154 - (0.912/T) 0.124 - (0.684/T) 0.175 - (0.841/T) None of these 0.154 - (0.912/T) 0.124 - (0.684/T) 0.175 - (0.841/T) None of these ANSWER DOWNLOAD EXAMIANS APP
Machine Design A closely coiled helical spring is acted upon by an axial force. The maximum shear stress developed in the spring is τ. The half of the length of the spring if cut off and the remaining spring is acted upon by the same axial force. The maximum shear stress in the spring in new condition will be τ τ/2 2 τ 4 τ τ τ/2 2 τ 4 τ ANSWER DOWNLOAD EXAMIANS APP
Machine Design If P1 and P2 are the tight and slack side tensions in the belt, then the initial tension Pi (according to Barth) will be equal to (Where, Pc is centrifugal tension) P1 + P2 [(√P1 + √P2)/2]² ⅟₂× (P1 + P2) [⅟₂ × (P1 + P2)] + Pc P1 + P2 [(√P1 + √P2)/2]² ⅟₂× (P1 + P2) [⅟₂ × (P1 + P2)] + Pc ANSWER DOWNLOAD EXAMIANS APP
Machine Design The strength of a riveted joint is equal to Shearing strength of rivet (Ps) Tearing strength of plate (Pt) Least value of Pt Ps and Pc Crushing strength of rivet (Pc) Shearing strength of rivet (Ps) Tearing strength of plate (Pt) Least value of Pt Ps and Pc Crushing strength of rivet (Pc) ANSWER DOWNLOAD EXAMIANS APP
Machine Design The ratio of belt tensions (p1/p2) considering centrifugal force in flat belt is given byWhere m = mass of belt per meter (kg/m)v = belt velocity (m/s)f = coefficient of frictiona = angle of wrap (radians) P1 / P2 = e–ᶠα (P1 - mv²)/ (P2 - mv²) = e–ᶠα (P1 - mv²)/ (P2 - mv²) = eᶠα P1 / P2 = eᶠα P1 / P2 = e–ᶠα (P1 - mv²)/ (P2 - mv²) = e–ᶠα (P1 - mv²)/ (P2 - mv²) = eᶠα P1 / P2 = eᶠα ANSWER DOWNLOAD EXAMIANS APP
Machine Design While designing a screw in a screw jack against buckling failure, the end conditions for the screw are taken as Both the ends fixed One end fixed and the other end hinged One end fixed and the other end free Both the ends hinged Both the ends fixed One end fixed and the other end hinged One end fixed and the other end free Both the ends hinged ANSWER DOWNLOAD EXAMIANS APP
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