Refrigeration and Air Conditioning In S.J. unit, one ton of refrigeration is equal to 840 kJ/ min 420 kJ/ min 210 kJ/ min 21 kJ/ min 840 kJ/ min 420 kJ/ min 210 kJ/ min 21 kJ/ min ANSWER DOWNLOAD EXAMIANS APP
Refrigeration and Air Conditioning The advantage of dry compression is that It results in high volumetric and mechanical efficiency It permits complete evaporation in the evaporator All of these It permits higher speeds to be used It results in high volumetric and mechanical efficiency It permits complete evaporation in the evaporator All of these It permits higher speeds to be used ANSWER DOWNLOAD EXAMIANS APP
Refrigeration and Air Conditioning The relative coefficient of performance is Actual COP × theoretical COP Actual COP/theoretical COP None of these Theoretical COP/actual COP Actual COP × theoretical COP Actual COP/theoretical COP None of these Theoretical COP/actual COP ANSWER DOWNLOAD EXAMIANS APP
Refrigeration and Air Conditioning The C.O.P. of an absorption type refrigerator is given by (where T₁ = Temperature at which the working substance receives heat, T₂ = Temperature of cooling water, and T₃ = Evaporator temperature) [T₃ (T₂ - T₃)] / [T₁ (T₁ - T₂)] [T₃ (T₁ - T₂)]/ [T₁ (T₂ - T₃)] [T₁ (T₂ - T₃)] / [T₃ (T₁ - T₂)] [T₁ (T₁ - T₂)] / [T₃ (T₂ - T₃)] [T₃ (T₂ - T₃)] / [T₁ (T₁ - T₂)] [T₃ (T₁ - T₂)]/ [T₁ (T₂ - T₃)] [T₁ (T₂ - T₃)] / [T₃ (T₁ - T₂)] [T₁ (T₁ - T₂)] / [T₃ (T₂ - T₃)] ANSWER DOWNLOAD EXAMIANS APP
Refrigeration and Air Conditioning In actual air-conditioning applications for R-12 and R-22, and operating at a condenser temperature of 40° C and an evaporator temperature of 5° C, the heat rejection factor is about 2.15 1.25 1 5.12 2.15 1.25 1 5.12 ANSWER DOWNLOAD EXAMIANS APP
Refrigeration and Air Conditioning The heat rejection factor (HRF) is given by 1 + C.O.P 1 - C.O.P. 1 + (1/C.O.P) 1 - (1/C.O.P) 1 + C.O.P 1 - C.O.P. 1 + (1/C.O.P) 1 - (1/C.O.P) ANSWER DOWNLOAD EXAMIANS APP
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