Hydraulics and Fluid Mechanics in ME In series-pipe problems the discharge through each pipe is added to obtain total discharge a trial solution is not necessary the head loss is same through each pipe the discharge is same through each pipe the discharge through each pipe is added to obtain total discharge a trial solution is not necessary the head loss is same through each pipe the discharge is same through each pipe ANSWER DOWNLOAD EXAMIANS APP
Hydraulics and Fluid Mechanics in ME In a short cylindrical external mouthpiece, the vena contracta occurs at a distance __________ the diameter of the orifice from the outlet of orifice. Equal to One-fourth One-half One-third Equal to One-fourth One-half One-third ANSWER DOWNLOAD EXAMIANS APP
Hydraulics and Fluid Mechanics in ME The total energy line lies over the hydraulic gradient line by an amount equal to the Pressure head + velocity head Pressure head Pressure head - velocity head Velocity head Pressure head + velocity head Pressure head Pressure head - velocity head Velocity head ANSWER DOWNLOAD EXAMIANS APP
Hydraulics and Fluid Mechanics in ME The resultant upward pressure of the fluid on an immersed body due to its tendency to uplift the sub-merged body is called upthrust reaction buoyancy metacentre upthrust reaction buoyancy metacentre ANSWER DOWNLOAD EXAMIANS APP
Hydraulics and Fluid Mechanics in ME Which of the following statement is correct as regard to water wheels? They have slow speeds They are suitable even for low water heads All of these They give constant efficiency, even if the discharge is not constant They have slow speeds They are suitable even for low water heads All of these They give constant efficiency, even if the discharge is not constant ANSWER DOWNLOAD EXAMIANS APP
Hydraulics and Fluid Mechanics in ME A tank of uniform cross-sectional area (A) containing liquid upto height (H1) has an orifice of cross-sectional area (a) at its bottom. The time required to bring the liquid level from H1 to H2 will be 2A × (√H₁ - √H₂)/Cd × a × √(2g) 2A × (√H3/2 - √H3/2)/Cd × a × √(2g) 2A × √H₂/Cd × a × √(2g) 2A × √H₁/Cd × a × √(2g) 2A × (√H₁ - √H₂)/Cd × a × √(2g) 2A × (√H3/2 - √H3/2)/Cd × a × √(2g) 2A × √H₂/Cd × a × √(2g) 2A × √H₁/Cd × a × √(2g) ANSWER DOWNLOAD EXAMIANS APP
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