Theory of Machine In its simplest form, a cam mechanism consists of following number of links 3 2 1 4 3 2 1 4 ANSWER DOWNLOAD EXAMIANS APP
Theory of Machine A rigid body, under the action of external forces, can be replaced by two masses placed at a fixed distance apart. The two masses form an equivalent dynamical system, if The sum of the two masses is equal to the total mass of body The center of gravity of the two masses coincides with that of the body All of these The sum of mass moment of inertia of the masses about their center of gravity is equal to the mass moment of inertia of the body The sum of the two masses is equal to the total mass of body The center of gravity of the two masses coincides with that of the body All of these The sum of mass moment of inertia of the masses about their center of gravity is equal to the mass moment of inertia of the body ANSWER DOWNLOAD EXAMIANS APP
Theory of Machine It is required to connect two parallel shafts, the distance between whose axes is small and variable. The shafts are coupled by Flexible coupling Oldham's coupling Knuckle joint Universal joint Flexible coupling Oldham's coupling Knuckle joint Universal joint ANSWER DOWNLOAD EXAMIANS APP
Theory of Machine The centre of gravity of a coupler link in a four bar mechanism will experience No acceleration Both linear and angular acceleration Only linear acceleration Only angular acceleration No acceleration Both linear and angular acceleration Only linear acceleration Only angular acceleration ANSWER DOWNLOAD EXAMIANS APP
Theory of Machine The example of rolling pair is Lead screw of a lathe Bolt and nut Ball bearing and roller bearing Ball and socket joint Lead screw of a lathe Bolt and nut Ball bearing and roller bearing Ball and socket joint ANSWER DOWNLOAD EXAMIANS APP
Theory of Machine The Kutzbach criterion for determining the number of degrees of freedom (n) is (where l = number of links, j = number of joints and h = number of higher pairs) n = 2(l - 1) - 2j - h n = 3(l - 1) - 3j - h n = 3(l - 1) - 2j - h n = 2(l - 1) - 3j - h n = 2(l - 1) - 2j - h n = 3(l - 1) - 3j - h n = 3(l - 1) - 2j - h n = 2(l - 1) - 3j - h ANSWER DOWNLOAD EXAMIANS APP
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