Mass Transfer In case of physical adsorption, the difference between heat of adsorption and heat of normal condensation is Equal to the heat of wetting Equal to the heat of formation of surface compound Called integral heat of adsorption Zero Equal to the heat of wetting Equal to the heat of formation of surface compound Called integral heat of adsorption Zero ANSWER DOWNLOAD EXAMIANS APP
Mass Transfer The individual mass transfer co-efficients (moles/m² . s) for absorption of a solute from a gas mixture into a liquid solvent are, KL = 4.5 and KG = 1.5. The slope of the equilibrium line is 3. Which of the following resistance (s) is (are) controlling ? Liquid side Both liquid and gas side Interfacial Gas side Liquid side Both liquid and gas side Interfacial Gas side ANSWER DOWNLOAD EXAMIANS APP
Mass Transfer Dew point of an air-water vapor mixture Corresponding to any point on the humidity chart is obtained by projecting a line through this point parallel to the temperature axis and to the saturation curve All of the listed here Decreases with decrease in pressure At constant humidity & total pressure is fixed Corresponding to any point on the humidity chart is obtained by projecting a line through this point parallel to the temperature axis and to the saturation curve All of the listed here Decreases with decrease in pressure At constant humidity & total pressure is fixed ANSWER DOWNLOAD EXAMIANS APP
Mass Transfer Design calculation for multiple component distillation is done by Tray to tray calculations Ponchon-Savarit method Mccabe-Thiele method Enthalpy concentration method Tray to tray calculations Ponchon-Savarit method Mccabe-Thiele method Enthalpy concentration method ANSWER DOWNLOAD EXAMIANS APP
Mass Transfer Mass transfer co-efficient is directly proportional to DAB according to the __________ theory. None of these Film Penetration Surface-renewal None of these Film Penetration Surface-renewal ANSWER DOWNLOAD EXAMIANS APP
Mass Transfer In a single stage extraction process, 10 kg of pure solvent S (containing no solute A) is mixed with 30 kg of feed F containing A at a mass fraction xf = 0.2. The mixture splits into an extract phase E and a raf-finate phase R containing A at xB = 0.5 and xR = 0.05 respectively. The total mass of the extract phase is (in Kg) 6.89 10 8.89 8.25 6.89 10 8.89 8.25 ANSWER DOWNLOAD EXAMIANS APP
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