Electrical Machines In an induction motor, air gap power is 10 Kw and mechanically developed power is 8 Kw. What are the rotor ohmic losses? 1.5KW 2KW 0.5Kw 3KW 1.5KW 2KW 0.5Kw 3KW ANSWER DOWNLOAD EXAMIANS APP
Electrical Machines Maximum power will be developed when back emf is double the supply voltage. half of the supply voltage. equal to supply voltage. All of these double the supply voltage. half of the supply voltage. equal to supply voltage. All of these ANSWER DOWNLOAD EXAMIANS APP
Electrical Machines If starting current of a 3 - Φ induction motor is 5 times the rated current, while rated slip is 4 %, then ratio of starting torque to full load torque is 0.6. 0.8. 1. 0.4. 0.6. 0.8. 1. 0.4. ANSWER DOWNLOAD EXAMIANS APP
Electrical Machines The starting resistance of DC motor is generally Low. 1000 ohms. Infinitely large. around 500 ohms. Low. 1000 ohms. Infinitely large. around 500 ohms. ANSWER DOWNLOAD EXAMIANS APP
Electrical Machines The counter (or back) emf in a dc machine is 1. the same as generated emf in a dc motor 2. proportional to field flux and armature speed 3. not the same as generated emf in a dc motor 4.inversely proportional to field flux 5. proportional to number of armature conductors 6. constant from no load to full load From these, the correct answer is 1, 2, 5 2, 4, 5, 6 2, 3, 6 3, 4, 5 1, 2, 5 2, 4, 5, 6 2, 3, 6 3, 4, 5 ANSWER DOWNLOAD EXAMIANS APP
Electrical Machines In a 3 - Φ IM with line frequency f1 and winding factor kw1 and kw2 for stator and rotor respectively the ratio of per phase stator winding emf E1 to per phase rotor winding emf E2 at standstill is given by E1 / E2 = f1kw1 / f2kw2. E1 / E2 = 1. E1 / E2 = N1 / N2. E1 / E2 = N1kw1 / N2kw2. E1 / E2 = f1kw1 / f2kw2. E1 / E2 = 1. E1 / E2 = N1 / N2. E1 / E2 = N1kw1 / N2kw2. ANSWER DOWNLOAD EXAMIANS APP
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