Area Problems In a triangle ABC, BC = 5 cm AC = 12 cm and AB = 13 cm. The length of a altitude drawn from B on AC is? 5 cm 7 cm 4 cm 6 cm 5 cm 7 cm 4 cm 6 cm ANSWER EXPLANATION DOWNLOAD EXAMIANS APP ? s= (13 + 5 + 12) / 2 cm = 15cms-a = 2 cm, s-b = 10 cm and s-c = 3 cm ? Area = ? (15 x 2 x 10 x 3 ) cm2= 30 cm2? (12 x h) / 2 = 30 ? h = 5 cm
Area Problems Area of a square is 1/2 hectare. The diagonal of the square is? 50 meter 50? 2 meter 250 meter 100 meter 50 meter 50? 2 meter 250 meter 100 meter ANSWER EXPLANATION DOWNLOAD EXAMIANS APP Area = 1/2 hectare = 10000 / 2 m2= 5000 m2Again Area = 1/2 x (Diagonal)2So 1/2 x (Diagonal)2 = 5000m2? Diagonal2= 10000 ? Diagonal = 100
Area Problems The length of hall is (4/3) times its breadth. If the area of hall be 300 square meters, the difference between the length and the breadth is? 4 meters 3 meters None of these 15 meters 4 meters 3 meters None of these 15 meters ANSWER EXPLANATION DOWNLOAD EXAMIANS APP Let breadth = b meters.Then, length = 4b/3 meters.? b x 4b/3 = 300? b2 = 300 x 3/4 ? b2 = 225? b = 15Hence, required difference = [(Length) - (Breadth) ]= 4b/3 - b = b/3= 15/3 m= 5 m
Area Problems Find the perimeter of a triangle with sides equal to 6 cm, 4 cm and 5 cm. 14 cm 18 cm 20 cm 15 cm 14 cm 18 cm 20 cm 15 cm ANSWER EXPLANATION DOWNLOAD EXAMIANS APP Given that, a = 6 cm, b = 4 cm and c = 5 cm Required perimeter = a + b + c= 6 + 4 + 5 cm = 15 cm
Area Problems A man walked diagonally across a square plot. Approximately what was the percent saved by not walking along the edges? 20% 10% 30% 40% 20% 10% 30% 40% ANSWER EXPLANATION DOWNLOAD EXAMIANS APP let the side of the square be x meterslength of two sides = 2x metersdiagonal = 2 x = 1.414x m saving on 2x meters = .59x m saving % = 0 . 59 x 2 x * 100 % = 30% (approx)
Area Problems The length of a rectangular plot is 20 metres more than its breadth. If the cost of fencing the plot @ 26.50 per metre is Rs. 5300, what is the length of the plot in metres? 40 None of these 120 Data inadequate 40 None of these 120 Data inadequate ANSWER EXPLANATION DOWNLOAD EXAMIANS APP Let breadth = x metres. Then, length = (x + 20) metres. Perimeter = ❨ 5300 ❩ m = 200 m. 26.50 ∴ 2[(x + 20) + x] = 200 ⟹ 2x + 20 = 100 ⟹ 2x = 80 ⟹ x = 40. Hence, length = x + 20 = 60 m
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