MGVCL Exam Paper (30-07-2021 Shift 2) In a single phase energy meter, the shunt electromagnet is energized by a ____of ____ current coil, thin wire of more turns pressure coil, thin wire of more turns pressure coil, thick wire of few turns current coil, thick wire of few turns current coil, thin wire of more turns pressure coil, thin wire of more turns pressure coil, thick wire of few turns current coil, thick wire of few turns ANSWER EXPLANATION DOWNLOAD EXAMIANS APP In single phase energy meter,Current coil is made up from thick wire having few no. of turns.Pressure coil is made up from thin wire having more no. of turns.
MGVCL Exam Paper (30-07-2021 Shift 2) સ્વાધીન' નો વિરોધીભાસી શબ્દ કયો છે? અસ્વાધીન નીસ્વધીન કુવાધીન પરાધીન અસ્વાધીન નીસ્વધીન કુવાધીન પરાધીન ANSWER DOWNLOAD EXAMIANS APP
MGVCL Exam Paper (30-07-2021 Shift 2) A coil having an inductance of 100 mH is magnetically coupled to another coil having an inductance of 900 mH. The coefficient of coupling between the coils is 0.45. Calculate the equivalent inductance if the two coils are connected in series opposing. 1270 mH 932 mH 1135 mH 730 mH 1270 mH 932 mH 1135 mH 730 mH ANSWER EXPLANATION DOWNLOAD EXAMIANS APP M = k√(L₁L₂)M= 0.45√(100*900)M = 135 mHL_eq for opposite connection of coils = L₁ + L₂ - 2ML_eq = 900 + 100 - 2*135L_eq = 730 mH
MGVCL Exam Paper (30-07-2021 Shift 2) Nangal Wildlife Sanctuary is located in which state? Sikkim Mizoram Punjab Tamil Nadu Sikkim Mizoram Punjab Tamil Nadu ANSWER DOWNLOAD EXAMIANS APP
MGVCL Exam Paper (30-07-2021 Shift 2) Encrypted security payload extension header is new in IPv5 IPv6 IP IPv4 IPv5 IPv6 IP IPv4 ANSWER DOWNLOAD EXAMIANS APP
MGVCL Exam Paper (30-07-2021 Shift 2) A circular loop has its radius increasing at a rate of 2 m/s. The loop is placed perpendicular to a constant magnetic field of 0.1 Wb/m². When the radius of the loop is 2 m, the emf induced in the loop will be 0.2π V zero 0.8π V 0.4π V 0.2π V zero 0.8π V 0.4π V ANSWER EXPLANATION DOWNLOAD EXAMIANS APP emf = dΨ/dt = change of flux linkageemf = dф/dtemf = d(B*Area)/dtemf = B*d(area)/dtemf = B*d(πr²)/dtemf = Bπ*2r*dr/dtemf = Bπ*2r*change of radius per unit timeemf = 0.1*π*2*2emf = 4π