Analog Electronics In a normally biased npn transistor, the electrons in the emitter have enough energy to overcome the barrier potential of the recombination path. base - emitter junction. collector - base junction. base - collector junction. recombination path. base - emitter junction. collector - base junction. base - collector junction. ANSWER DOWNLOAD EXAMIANS APP
Analog Electronics In the second approximation, the total voltage across the zener diode is the sum of the breakdown voltage and the voltage across the zener resistance. source. zener diode. series resistor. zener resistance. source. zener diode. series resistor. ANSWER DOWNLOAD EXAMIANS APP
Analog Electronics The load voltage is approximately constant when a zener diode is unbiased. reverse biased. operating in breakdown region. forward biased. unbiased. reverse biased. operating in breakdown region. forward biased. ANSWER DOWNLOAD EXAMIANS APP
Analog Electronics In a loaded zener regulator, which is the largest current? None of these Load current. Zener current. Series current. None of these Load current. Zener current. Series current. ANSWER DOWNLOAD EXAMIANS APP
Analog Electronics The reverse saturation electric current of a pn junction varies with temperature (T) as 1 / T. T2. independent of T. T. 1 / T. T2. independent of T. T. ANSWER DOWNLOAD EXAMIANS APP
Analog Electronics An npn BJT has gm=38mA/v, cµ =10¯14 F, cπ =10¯13F and DC current gain β0=90.For this transistor fT & fβ are fT =1.64 x 108 Hz & fβ = 1.47 x 1010 Hz fT =1.33 x 1012 Hz & fβ = 1.47 x 1010 Hz fT =1.47 x 1010 Hz & fβ = 1.64 x 108 Hz fT =1.47 x 1010 Hz & fβ = 1.33 x 1012 Hz fT =1.64 x 108 Hz & fβ = 1.47 x 1010 Hz fT =1.33 x 1012 Hz & fβ = 1.47 x 1010 Hz fT =1.47 x 1010 Hz & fβ = 1.64 x 108 Hz fT =1.47 x 1010 Hz & fβ = 1.33 x 1012 Hz ANSWER DOWNLOAD EXAMIANS APP
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