Machine Design In a full journal bearing, the angle of contact of the bearing with the journal is 360° 270° 120° 180° 360° 270° 120° 180° ANSWER DOWNLOAD EXAMIANS APP
Machine Design Basic hole is one Whose lower deviation is zero Whose upper deviation is zero Whose lower as well as upper deviations are zero Does not exist Whose lower deviation is zero Whose upper deviation is zero Whose lower as well as upper deviations are zero Does not exist ANSWER DOWNLOAD EXAMIANS APP
Machine Design Which of the following statement is wrong for a connecting rod? The connecting rod will be equally strong in buckling about X-axis and Y-axis, if Ixx = 4 Iyy If Ixx > 4 Iyy, the buckling will occur about Y-axis The most suitable section for the connecting rod is T-section If Ixx < 4 Iyy, the buckling will occur about X-axis The connecting rod will be equally strong in buckling about X-axis and Y-axis, if Ixx = 4 Iyy If Ixx > 4 Iyy, the buckling will occur about Y-axis The most suitable section for the connecting rod is T-section If Ixx < 4 Iyy, the buckling will occur about X-axis ANSWER DOWNLOAD EXAMIANS APP
Machine Design If two springs are in parallel then their overall stiffness will be Half Double None of these Same Half Double None of these Same ANSWER DOWNLOAD EXAMIANS APP
Machine Design An Involute pinion and gear are in mesh. If both have the same size of addendum, then there will be interference between the Tip of both gear and pinion Tip of the pinion and flank of gear Tip of the gear and flank of pinion Flanks of both gear and pinion Tip of both gear and pinion Tip of the pinion and flank of gear Tip of the gear and flank of pinion Flanks of both gear and pinion ANSWER DOWNLOAD EXAMIANS APP
Machine Design In a band and block brake, the ratio of tensions on the tight and slack sides of band is given by (where μ = Coefficient of friction between the blocks and the drum, θ = Semi-angle of each block subtending at the centre of drum, and n = Number of blocks) T₁/T₂ = [(1 - μ tanθ)/ (1 + μ tanθ)]n T₁/T₂ = [(1 + μ tanθ)/ (1 - μ tanθ)]n T₁/T₂ = μθ × n T₁/T₂ = (μθ)n T₁/T₂ = [(1 - μ tanθ)/ (1 + μ tanθ)]n T₁/T₂ = [(1 + μ tanθ)/ (1 - μ tanθ)]n T₁/T₂ = μθ × n T₁/T₂ = (μθ)n ANSWER DOWNLOAD EXAMIANS APP
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