Process Equipment and Plant Design In a double pipe concentric heat exchanger, the equivalent diameter of annulus for heat transfer would be (where, D₁ and D₂ are I.D. of inner and outer pipes) (D₂² - D₁²)/D₂² (D₂² - D₁²)/D₁² None of these D₂ - D₁ (D₂² - D₁²)/D₂² (D₂² - D₁²)/D₁² None of these D₂ - D₁ ANSWER DOWNLOAD EXAMIANS APP
Process Equipment and Plant Design 1.2 to 3.8 cms is the value of the Downcomer liquid seal in case of a balanced tray design Skirt clearance for bubble caps Static submergence in case of a bubble cap tray for column operating under pressure (≥ 1 atm.) All of these Downcomer liquid seal in case of a balanced tray design Skirt clearance for bubble caps Static submergence in case of a bubble cap tray for column operating under pressure (≥ 1 atm.) All of these ANSWER DOWNLOAD EXAMIANS APP
Process Equipment and Plant Design For a 25 mm hole drilled in plates to be rivetted, the shank diameter of the rivet should be __________ mm. 25 23 27 26 25 23 27 26 ANSWER DOWNLOAD EXAMIANS APP
Process Equipment and Plant Design With increase in temperature drop (in a shell and tube heat exchanger), the LMTD correction factor, FT Remains constant Decreases very rapidly Increases very rapidly Increases linearly Remains constant Decreases very rapidly Increases very rapidly Increases linearly ANSWER DOWNLOAD EXAMIANS APP
Process Equipment and Plant Design Value of Peclet number = 0, is the representative of Plug flow Laminar flow Eddy diffusivity = 0 Complete back mixing Plug flow Laminar flow Eddy diffusivity = 0 Complete back mixing ANSWER DOWNLOAD EXAMIANS APP
Process Equipment and Plant Design For turbulent flow (NRe > 2100) of low viscosity fluid (μ > 20cp) in steel pipes, the optimum inside pipe diameter is given by(where, Q = fluid flow rate, ft³/sec.ρ = fluid density, lb/ft³ μ = fluid viscosity, centipoise Di = optimum inside pipe diameter, inches) Di, opt = 4.7 Q0.36 . μ3.2ρ0.13 Di, opt = 3.9 Q0.45 ρ0.13 Di, opt = 3.9 Q0.45 . μ0.95 Di, opt = 3 Q0.36 . μ0.88 Di, opt = 4.7 Q0.36 . μ3.2ρ0.13 Di, opt = 3.9 Q0.45 ρ0.13 Di, opt = 3.9 Q0.45 . μ0.95 Di, opt = 3 Q0.36 . μ0.88 ANSWER DOWNLOAD EXAMIANS APP
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