Engineering Thermodynamics In a Carnot cycle, heat is transferred at Constant pressure Constant temperature Constant enthalpy Constant volume Constant pressure Constant temperature Constant enthalpy Constant volume ANSWER DOWNLOAD EXAMIANS APP
Engineering Thermodynamics The index of compression ‘n’ tends to reach ratio of specific heats ‘y’ when Process is isothermal Process is isentropic and specific heat does not change with temperature Process is isentropic Flow is uniform and steady Process is isothermal Process is isentropic and specific heat does not change with temperature Process is isentropic Flow is uniform and steady ANSWER DOWNLOAD EXAMIANS APP
Engineering Thermodynamics Energy can neither be created nor destroyed but can be converted from one form to other is inferred from Zeroth low of thermodynamic First law of thermodynamics Basic law of thermodynamics Second law to thermodynamics Zeroth low of thermodynamic First law of thermodynamics Basic law of thermodynamics Second law to thermodynamics ANSWER DOWNLOAD EXAMIANS APP
Engineering Thermodynamics The thermal efficiency of an ideal gas turbine plant is given by (where r = Pressure ratio) 1 - rγ - 1 1 - (1/r) γ - 1/ γ 1 - (1/r) γ/γ - 1 rγ - 1 1 - rγ - 1 1 - (1/r) γ - 1/ γ 1 - (1/r) γ/γ - 1 rγ - 1 ANSWER DOWNLOAD EXAMIANS APP
Engineering Thermodynamics The condition for the reversibility of a cycle is All of these All the processes, taking place in the cycle of operation, must be extremely slow The pressure and temperature of the working substance must not differ, appreciably, from those of the surroundings at any stage in the process The working parts of the engine must be friction free All of these All the processes, taking place in the cycle of operation, must be extremely slow The pressure and temperature of the working substance must not differ, appreciably, from those of the surroundings at any stage in the process The working parts of the engine must be friction free ANSWER DOWNLOAD EXAMIANS APP
Engineering Thermodynamics The heat absorbed or rejected by the working substance is given by (where ds = Increase or decrease of entropy, T = Absolute temperature, and dQ = Heat absorbed or rejected) dQ = ds/T δQ = T.ds None of the listed here δQ = T/ds dQ = ds/T δQ = T.ds None of the listed here δQ = T/ds ANSWER DOWNLOAD EXAMIANS APP
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