Engineering Thermodynamics The efficiency of Diesel cycle depends upon Compression ratio Pressure ratio Cut-off ratio and compression ratio Temperature limits Compression ratio Pressure ratio Cut-off ratio and compression ratio Temperature limits ANSWER DOWNLOAD EXAMIANS APP
Engineering Thermodynamics Which of the following processes are thermodynamically reversible? Isothermal and adiabatic Constant volume and constant pressure Throttling Free expansion Isothermal and adiabatic Constant volume and constant pressure Throttling Free expansion ANSWER DOWNLOAD EXAMIANS APP
Engineering Thermodynamics The efficiency of a gas turbine is given by (Net work output)/(Work-done by the turbine) (Actual temperature drop)/(Isentropic temperature drop) (Isentropic increase in temperature)/(Actual increase in temperature) (Net work output)/(Heat supplied) (Net work output)/(Work-done by the turbine) (Actual temperature drop)/(Isentropic temperature drop) (Isentropic increase in temperature)/(Actual increase in temperature) (Net work output)/(Heat supplied) ANSWER DOWNLOAD EXAMIANS APP
Engineering Thermodynamics The gas constant (R) is equal to the Difference of two specific heats Product of two specific heats Ratio of two specific heats Sum of two specific heats Difference of two specific heats Product of two specific heats Ratio of two specific heats Sum of two specific heats ANSWER DOWNLOAD EXAMIANS APP
Engineering Thermodynamics Zeroth law of thermodynamics Deals with reversibility and irreversibility of process States that if two systems are both in equilibrium with a third system, they are in thermal equilibrium with each other Deals with conversion of mass and energy Deals with heat engines Deals with reversibility and irreversibility of process States that if two systems are both in equilibrium with a third system, they are in thermal equilibrium with each other Deals with conversion of mass and energy Deals with heat engines ANSWER DOWNLOAD EXAMIANS APP
Engineering Thermodynamics A gas is compressed in a cylinder by a movable piston to a volume one half its original volume. During the process 300 kJ heat left the gas and internal energy remained same. The work done on gas in Nm will be 30 Nm 300 Nm 300,000 Nm 3000 Nm 30 Nm 300 Nm 300,000 Nm 3000 Nm ANSWER DOWNLOAD EXAMIANS APP
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