Mass Transfer If f = moles of vapour present per mole of feed, then the slope of feed line is - (f - 1)/f - 1/f (1 - f)/f - f/(1 - f) - (f - 1)/f - 1/f (1 - f)/f - f/(1 - f) ANSWER DOWNLOAD EXAMIANS APP
Mass Transfer If the solubilities of different components (in a liquid-liquid extraction system) increase with rise in temperature, then the temperature above which they dissolve completely is known as the critical solution temperature (CST or consolute temperature). If solubilities increase with decrease in temperature, then CST is the temperature below which they dissolve completely. If a binary system has no critical solution temperature, it implies that The system comprises of an azeotrope The system comprises of miscible liquids On heating, a vapor phase will appear ; while on cooling, a solid phase will appear The system comprises of partially mis-cible liquids The system comprises of an azeotrope The system comprises of miscible liquids On heating, a vapor phase will appear ; while on cooling, a solid phase will appear The system comprises of partially mis-cible liquids ANSWER DOWNLOAD EXAMIANS APP
Mass Transfer For the flow of gases through a capillary, with increase in temperature, the permeability __________ as per Knudsen law. Remains same Either A or B; depends on the gas Increases Decreases Remains same Either A or B; depends on the gas Increases Decreases ANSWER DOWNLOAD EXAMIANS APP
Mass Transfer To increase the absorption factor, (where, G = gas flow rate, S = solvent flow rate) Decrease both 'G' and 'S' Increase 'G' and decrease 'S' Increase 'S' and decrease 'G' Increase both 'G' and 'S' Decrease both 'G' and 'S' Increase 'G' and decrease 'S' Increase 'S' and decrease 'G' Increase both 'G' and 'S' ANSWER DOWNLOAD EXAMIANS APP
Mass Transfer Molecular seives are regenerated by heating to __________ °C. > 500 < 150 > 1000 200-330 > 500 < 150 > 1000 200-330 ANSWER DOWNLOAD EXAMIANS APP
Mass Transfer The absorption factor is defined as (where, L = liquid flow rate, G = gas flow rate and, m = slope of the equilibrium line) ML/G G/mL L/mG LG/m ML/G G/mL L/mG LG/m ANSWER DOWNLOAD EXAMIANS APP