Surveying If ‘δ’ is the declination of the Polaris and ‘λ’ is the latitude of the place, the azimuth of the Polaris, is sin (90° - δ)/sin (90° - λ) cos (90° - δ)/cos (90° - λ) cos δ/cos λ tan (90° + δ)/tan (90° + λ) sin (90° - δ)/sin (90° - λ) cos (90° - δ)/cos (90° - λ) cos δ/cos λ tan (90° + δ)/tan (90° + λ) ANSWER DOWNLOAD EXAMIANS APP
Surveying The rate of change of parallax dp/dh with respect to change in h, may be expressed as fB/(H + h)² fB/(H + h) fB/(H - h)² fB/(H - h) fB/(H + h)² fB/(H + h) fB/(H - h)² fB/(H - h) ANSWER DOWNLOAD EXAMIANS APP
Surveying The adjustment of horizontal cross hair is required particularly when the instrument is used for measurement of horizontal angles prolonging a straight line leveling All of these measurement of horizontal angles prolonging a straight line leveling All of these ANSWER DOWNLOAD EXAMIANS APP
Surveying The solar tidal force divided by lunar tidal force is 1/3 1/2 3/4 5/4 1/3 1/2 3/4 5/4 ANSWER DOWNLOAD EXAMIANS APP
Surveying The correction applied to the measured base of length ‘L’ is All of these Slope = (h²/2L) + (h⁴/8L³) where h is height difference of end supports Tension = (P - Ps)L/AE Sag = L³w²/24P² where w is the weight of tape/m All of these Slope = (h²/2L) + (h⁴/8L³) where h is height difference of end supports Tension = (P - Ps)L/AE Sag = L³w²/24P² where w is the weight of tape/m ANSWER DOWNLOAD EXAMIANS APP
Surveying The longitudes of two places at latitude 60° N are 93° E and 97° W. Their departure is 5100 nautical miles 500 nautical miles 5700 nautical miles 120 nautical miles 5100 nautical miles 500 nautical miles 5700 nautical miles 120 nautical miles ANSWER DOWNLOAD EXAMIANS APP
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