Surveying If α is the observed altitude, the refraction correction in seconds, is 58" cot α 58 sin α 58" tan α 58 cos α 58" cot α 58 sin α 58" tan α 58 cos α ANSWER DOWNLOAD EXAMIANS APP
Surveying If θ and δ be the latitude of an observer and declination of a heavenly body respectively, the upper culmination of the body will be south of zenith if its zenith distance, is θ - δ δ - θ ½ (θ - δ) θ + δ θ - δ δ - θ ½ (θ - δ) θ + δ ANSWER DOWNLOAD EXAMIANS APP
Surveying The most convenient co-ordinate system for specifying the relative positions of heavenly bodies on the celestial sphere, is Declination and right ascension system Declination and altitude system Altitude and azimuth system Declination and hour angle system Declination and right ascension system Declination and altitude system Altitude and azimuth system Declination and hour angle system ANSWER DOWNLOAD EXAMIANS APP
Surveying G.M.T. corresponding to given mean time, equals L.M.T. - East longitude in time None of these L.M.T. - West longitude in time L.M.T. + East longitude in time L.M.T. - East longitude in time None of these L.M.T. - West longitude in time L.M.T. + East longitude in time ANSWER DOWNLOAD EXAMIANS APP
Surveying The want of correspondence in stereo-photographs Is minimum when θ is 3° Is not affected by the change of flying height between photographs Is a function of tilt Is a good property Is minimum when θ is 3° Is not affected by the change of flying height between photographs Is a function of tilt Is a good property ANSWER DOWNLOAD EXAMIANS APP
Surveying The correction applied to the measured base of length ‘L’ is All of these Sag = L³w²/24P² where w is the weight of tape/m Tension = (P - Ps)L/AE Slope = (h²/2L) + (h⁴/8L³) where h is height difference of end supports All of these Sag = L³w²/24P² where w is the weight of tape/m Tension = (P - Ps)L/AE Slope = (h²/2L) + (h⁴/8L³) where h is height difference of end supports ANSWER DOWNLOAD EXAMIANS APP
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