Surveying From the principal point the horizon point lies on the principal line at a distance of f cos θ f cot θ f sin θ f tan θ f cos θ f cot θ f sin θ f tan θ ANSWER DOWNLOAD EXAMIANS APP
Surveying The correction applied to the measured base of length ‘L’ is Tension = (P - Ps)L/AE Sag = L³w²/24P² where w is the weight of tape/m All of these Slope = (h²/2L) + (h⁴/8L³) where h is height difference of end supports Tension = (P - Ps)L/AE Sag = L³w²/24P² where w is the weight of tape/m All of these Slope = (h²/2L) + (h⁴/8L³) where h is height difference of end supports ANSWER DOWNLOAD EXAMIANS APP
Surveying The rise and fall method of levelling provides a complete check on All of these foresight backsight intermediate sight All of these foresight backsight intermediate sight ANSWER DOWNLOAD EXAMIANS APP
Surveying The orthogonal projection of the perspective centre on a tilted photograph, is called Plumb point Isocenter Nadir Principal point Plumb point Isocenter Nadir Principal point ANSWER DOWNLOAD EXAMIANS APP
Surveying A negative declination shows that the magnetic meridian is to the southern side of the true meridian western side of the true meridian eastern side of the true meridian None of these southern side of the true meridian western side of the true meridian eastern side of the true meridian None of these ANSWER DOWNLOAD EXAMIANS APP
Surveying A plate parallel is the line on the plane of the negative Along the bisector of the angle between the principal line and a perpendicular line through principal plane Parallel to the principal line Perpendicular to the principal line None of these Along the bisector of the angle between the principal line and a perpendicular line through principal plane Parallel to the principal line Perpendicular to the principal line None of these ANSWER DOWNLOAD EXAMIANS APP
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