Machine Design For a shaft diameter of 200 mm, the number of bolts in a marine flange coupling should be 8 6 10 4 8 6 10 4 ANSWER DOWNLOAD EXAMIANS APP
Machine Design The rolling contact bearings as compared to sliding contact bearings have Small overall dimensions Accuracy of shaft alignment All of these Low starting and low running friction except at very high speeds Small overall dimensions Accuracy of shaft alignment All of these Low starting and low running friction except at very high speeds ANSWER DOWNLOAD EXAMIANS APP
Machine Design According to Indian standard specifications, 100 H6/g5 means that Tolerance grade for the shaft is 4 to 8 and for the hole is 3 to 7 Tolerance grade for the hole is 6 and for the shaft is 5 Tolerance grade for the hole is 4 to 8 and for the shaft is 3 to 7 Tolerance grade for the shaft is 6 and for the hole is 5 Tolerance grade for the shaft is 4 to 8 and for the hole is 3 to 7 Tolerance grade for the hole is 6 and for the shaft is 5 Tolerance grade for the hole is 4 to 8 and for the shaft is 3 to 7 Tolerance grade for the shaft is 6 and for the hole is 5 ANSWER DOWNLOAD EXAMIANS APP
Machine Design The material used for brake lining should have __________ coefficient of friction. Moderate High None of these Low Moderate High None of these Low ANSWER DOWNLOAD EXAMIANS APP
Machine Design The load cup of a screw jack is made separate from the head of the spindle to Enhance the load carrying capacity of the jack Reduce the value of frictional torque Reduce the effort needed for lifting the working load Prevent the rotation of load being lifted Enhance the load carrying capacity of the jack Reduce the value of frictional torque Reduce the effort needed for lifting the working load Prevent the rotation of load being lifted ANSWER DOWNLOAD EXAMIANS APP
Machine Design According to I.B.R., shearing resistance required to shear off the rivet per pitch length (in double shear) is (where n = Number of rivets per pitch length) (π/4) d² × τ × n 2 × (π/4) d² × τ × n 1.875 × (π/4) d² × τ × n 3 × (π/4) d² × τ × n (π/4) d² × τ × n 2 × (π/4) d² × τ × n 1.875 × (π/4) d² × τ × n 3 × (π/4) d² × τ × n ANSWER DOWNLOAD EXAMIANS APP