Given expression [(0.3333)/(0.2222)] x [((0.1667)(0.8333)) / ((0.6667)(0.1250))]=[(3333 / 2222)] x [((1/6) x (5/6)) / ((2/3) x (125/1000))]=[(3/2) x (1/6) x (5/6) x (3/2) x 8]=5 / 2=2.50
Sum of the decimal places = 7 .Since the last digit to the extreme right will be zero ( 5 * 4 = 20), so there will be 6 significant digits to the right of the decimal point....
EXAMIANS