Engineering Mechanics On a ladder resting on smooth ground and leaning against vertical wall, the force of friction will be Upwards at its upper end Downwards at its upper end Towards the wall at its upper end Away from the wall at its upper end Upwards at its upper end Downwards at its upper end Towards the wall at its upper end Away from the wall at its upper end ANSWER DOWNLOAD EXAMIANS APP
Engineering Mechanics On the ladder resting on the ground and leaning against a smooth vertical wall, the force of friction will be Perpendicular to the wall at its upper end Upwards at its upper end Downwards at its upper end Zero at its upper end Perpendicular to the wall at its upper end Upwards at its upper end Downwards at its upper end Zero at its upper end ANSWER DOWNLOAD EXAMIANS APP
Engineering Mechanics Moment of inertia of a circular section about its diameter (d) is πd3/32 πd3/16 πd4/64 πd4/32 πd3/32 πd3/16 πd4/64 πd4/32 ANSWER DOWNLOAD EXAMIANS APP
Engineering Mechanics The range of projectile (R) on an upward inclined plane is g. cos² β/2u². sin (α + β). cos α 2u². sin (α + β). cos α/g. cos² β 2u². sin (α - β). cos α/g. cos² β g. cos² β/2u². sin (α - β). cos α g. cos² β/2u². sin (α + β). cos α 2u². sin (α + β). cos α/g. cos² β 2u². sin (α - β). cos α/g. cos² β g. cos² β/2u². sin (α - β). cos α ANSWER DOWNLOAD EXAMIANS APP
Engineering Mechanics If a number of forces are acting at a point, their resultant will be inclined at an angle 'θ' with the horizontal, such that tanθ = ΣV × ΣH tanθ = ΣV/ΣH tanθ = ΣH/ΣV tanθ = √(ΣV + ΣH) tanθ = ΣV × ΣH tanθ = ΣV/ΣH tanθ = ΣH/ΣV tanθ = √(ΣV + ΣH) ANSWER DOWNLOAD EXAMIANS APP
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