Power Systems Condition for maximum voltage regulation cosφ = X/R tanφ = X/R cosφ = R/X tanφ = R/X cosφ = X/R tanφ = X/R cosφ = R/X tanφ = R/X ANSWER DOWNLOAD EXAMIANS APP
Power Systems The internal flux linkage due to internal flux of a conductor is I/4*10-7 wb-T/m I/2*10-7 wb-T/m All of these I/6*10-7 wb-T/m I/4*10-7 wb-T/m I/2*10-7 wb-T/m All of these I/6*10-7 wb-T/m ANSWER DOWNLOAD EXAMIANS APP
Power Systems Plug setting of a relay can be altered by varying air gap of magnetic path. adjustable back up stop. no. of ampere-turns. none of these. air gap of magnetic path. adjustable back up stop. no. of ampere-turns. none of these. ANSWER DOWNLOAD EXAMIANS APP
Power Systems What should be the minimum depth (in metre)of cable trench to dug for laying of 1.1 kV? 0.75. 1.05. 1.20. 0.90. 0.75. 1.05. 1.20. 0.90. ANSWER DOWNLOAD EXAMIANS APP
Power Systems A transmission line has a reactance of 1 Pu is operating at Vs = Vr = 1 Pu. The generator is connected at source end which is delivering 0.5 Pu of active power and the transmission line is compensated with a series capacitance of 0.5 Pu. Find the load angle with series capacitance compensation ? 29° 14.5° 10.5° 35.5° 29° 14.5° 10.5° 35.5° ANSWER DOWNLOAD EXAMIANS APP
Power Systems Consider a three phase, 50 Hz, 11 kV distribution system. Each of the conductors is suspended by an insulator string having two identical porcelain insulators. The self capacitance of the insulators is 5 times the shunt capacitance between the link and ground. Find the voltage across the two insulators V1 and V2? (V1 = Voltage of disc nearest to the conductor) V1 = 5 kV and V2 = 6 kV V1 = 3.46 kV and V2 = 2.89 kV V1 = 2.89 kV and V2 = 3.46 kV V1 = 6 kV and V2 = 5 kV V1 = 5 kV and V2 = 6 kV V1 = 3.46 kV and V2 = 2.89 kV V1 = 2.89 kV and V2 = 3.46 kV V1 = 6 kV and V2 = 5 kV ANSWER DOWNLOAD EXAMIANS APP
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