Electrical Machines Armature resistance control method is used for the _______ ? both 1 and 2 below rated speed None of these above rated speed both 1 and 2 below rated speed None of these above rated speed ANSWER DOWNLOAD EXAMIANS APP
Electrical Machines A 3-φ alternator has negligible stator resistance. A short circuit test is conducted on this alternator. At a particular speed, a field current of If1 is required to drive the rated armature current. If the speed of the alternator is reduced to half, the field current required to maintain rated armature current Cannot be predicted due to insufficient data. Would be equal to If1/2. Would be equal to If1. Woud be equal to 2If1. Cannot be predicted due to insufficient data. Would be equal to If1/2. Would be equal to If1. Woud be equal to 2If1. ANSWER DOWNLOAD EXAMIANS APP
Electrical Machines The interpoles in dc machines have a tapering shape in order to increase the acceleration of commutation reduce the saturation in the interpole economise on the material required for interpoles and their windings reduce the overall weight increase the acceleration of commutation reduce the saturation in the interpole economise on the material required for interpoles and their windings reduce the overall weight ANSWER DOWNLOAD EXAMIANS APP
Electrical Machines On switching a DC motor to DC supply mains, it is found to rotate in the direction opposite to that for which it is designed. The DC motor is Differentical compound. have an equal number of electrons and protons. Series shunt. Cummulative compound. Differentical compound. have an equal number of electrons and protons. Series shunt. Cummulative compound. ANSWER DOWNLOAD EXAMIANS APP
Electrical Machines Commutator in DC generator is used for reduce losses convert AC armature current in to DC increase efficiency collecting of current reduce losses convert AC armature current in to DC increase efficiency collecting of current ANSWER DOWNLOAD EXAMIANS APP
Electrical Machines For P pole machine relation between electrical degrees and mechanical degrees is θelec = 4/P*θmech θelec = 2/P*θmech θelec = θmech θelec = P/2*θmech θelec = 4/P*θmech θelec = 2/P*θmech θelec = θmech θelec = P/2*θmech ANSWER DOWNLOAD EXAMIANS APP
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