Hydraulics and Fluid Mechanics in ME According to fan laws, for fans having constant wheel diameter, the air or gas capacity varies Directly as fan speed Square of fan speed Cube of fan speed Square root of fan speed Directly as fan speed Square of fan speed Cube of fan speed Square root of fan speed ANSWER DOWNLOAD EXAMIANS APP
Hydraulics and Fluid Mechanics in ME A vertically immersed surface is shown in the below figure. The distance of its centre of pressure from the water surface is b²/12 + x̅ (bd²/12) + x̅ d²/12 + x̅ (d²/12 x̅) + x̅ b²/12 + x̅ (bd²/12) + x̅ d²/12 + x̅ (d²/12 x̅) + x̅ ANSWER DOWNLOAD EXAMIANS APP
Hydraulics and Fluid Mechanics in ME Impulse turbine is generally fitted About 2.5 m above the tail race to avoid cavitations Slightly below the tail race Little above the tail race At the level of tail race About 2.5 m above the tail race to avoid cavitations Slightly below the tail race Little above the tail race At the level of tail race ANSWER DOWNLOAD EXAMIANS APP
Hydraulics and Fluid Mechanics in ME Coefficient of discharge Cd is equal to (where Cc = Coefficient of contraction, Cv = Coefficient of velocity, and Cr = Coefficient of resistance) Cv × Cr Cc × Cv Cc × Cr Cc/Cr Cv × Cr Cc × Cv Cc × Cr Cc/Cr ANSWER DOWNLOAD EXAMIANS APP
Hydraulics and Fluid Mechanics in ME A piece of metal of specific gravity 13.6 is placed in mercury of specific gravity 13.6, what fraction of it volume is under mercury? The metal piece will simply float over the mercury Metal piece will sink to the bottom Whole of the metal piece will be immersed with its top surface just at mercury level The metal piece will be immersed in mercury by half The metal piece will simply float over the mercury Metal piece will sink to the bottom Whole of the metal piece will be immersed with its top surface just at mercury level The metal piece will be immersed in mercury by half ANSWER DOWNLOAD EXAMIANS APP
Hydraulics and Fluid Mechanics in ME The discharge through an external mouthpiece is given by (where a = Cross-sectional area of the mouthpiece, and H = Height of liquid above the mouthpiece) 0.855 a.√(2gH) 1.585 a.√(2gH) 5.85 aH.√(2g) 1.855 aH.√(2g) 0.855 a.√(2gH) 1.585 a.√(2gH) 5.85 aH.√(2g) 1.855 aH.√(2g) ANSWER DOWNLOAD EXAMIANS APP
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