Alligation or Mixture problems A vessel, full of water, weighs 24 kg. When the vessel is 1/4 full, it weighs 9 kg. Find the weight of empty vessel. 5 kg 4 kg 8 kg 3 kg 5 kg 4 kg 8 kg 3 kg ANSWER EXPLANATION DOWNLOAD EXAMIANS APP Let the weight of vessel be xWeight of water = 24 ? x? (24 ? x)/4 + x = 9? 24 ? x + 4x = 36? 3x = 12? x = 4 kg
Alligation or Mixture problems In what ratio of water be mixed with milk to gain 16 2/ 3 % on selling the mixture at cost price? 2 : 3 1 : 6 6 : 1 4 : 3 2 : 3 1 : 6 6 : 1 4 : 3 ANSWER EXPLANATION DOWNLOAD EXAMIANS APP Let C.P. of 1 liter milk be Re. 1, Gain = 16 2/3 % = 50/3 %and S.P. of 1 liter mixture = Re. 1 then C.P. of 1 liter mixture = (1 x (100 x 3) / 350) = Re. (6 / 7) By the rule of alligation,Hence, required ratio = (1/ 7) : (6 / 7) = 1 : 6
Alligation or Mixture problems How much water (in litres) must be added to 80 litres solution of milk and water containing 10% milk, so that it becomes a 5% milk solution? 10 80 40 20 10 80 40 20 ANSWER EXPLANATION DOWNLOAD EXAMIANS APP Let initial quantity be Q, and final quantity be F F = Q(1 - 8/Q) 4 => Q = 20
Alligation or Mixture problems Two bottles contain acid and water in the ratio 2 : 3 and 1 : 2 respectively. These are mixed in the ratio 1 : 3. What is the ratio of acid and water in the new mixture ? 7:13 11:57 23:37 1:3 7:13 11:57 23:37 1:3 ANSWER DOWNLOAD EXAMIANS APP
Alligation or Mixture problems The ratio of milk and water in three samples is 1 : 3, 3 : 5 and 11 : 5. A mixture containing equal quantities of all three samples is made. What will be the ratio of milk and water in the new mixture? 7 : 9 5 : 7 9 : 11 15 : 13 7 : 9 5 : 7 9 : 11 15 : 13 ANSWER DOWNLOAD EXAMIANS APP
Alligation or Mixture problems A tin a mixture of two liquids A and B in the proportion 4 : 1. If 45 litres of the mixture is replaced by 45 litres of liquid B, then the ratio of the two liquids becomes 2 : 5. How much of the liquid B was there in the tin? What quantity does the tin hold? 62 l 58 l 50 l 65 l 62 l 58 l 50 l 65 l ANSWER EXPLANATION DOWNLOAD EXAMIANS APP Let the tin contain 5x litres of liquids 5 x - 45 x 4 5 5 x - 45 x 1 5 + 45 = 2 5 => 5(4x - 36) = 2(x + 36) => 20x - 180 = 2x + 72 => x = 14 litres Hence, the initial quantity of mixture = 70l Quantity of liquid B = 70 - 45 x 1 5 + 45 = 50 litres.
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