Theory of Structures A steel bar 20 mm in diameter simply-supported at its ends over a total span of 40 cm carries a load at its centre. If the maximum stress induced in the bar is limited to N/mm², the bending strain energy stored in the bar, is 511 N mm 611 N mm 411 N mm 711 N mm 511 N mm 611 N mm 411 N mm 711 N mm ANSWER DOWNLOAD EXAMIANS APP
Theory of Structures A lift of weight W is lifted by a rope with an acceleration f. If the area of cross-section of the rope is A, the stress in the rope is (1 – g/f)/A [W (1 + f/ G)]/ A [W (2 + g/f)]/A [W (2 + f/G)]/A (1 – g/f)/A [W (1 + f/ G)]/ A [W (2 + g/f)]/A [W (2 + f/G)]/A ANSWER DOWNLOAD EXAMIANS APP
Theory of Structures At any point of a beam, the section modulus may be obtained by dividing the moment of inertia of the section by Maximum tensile stress at the section Depth of the neutral axis Depth of the section Maximum compressive stress at the section Maximum tensile stress at the section Depth of the neutral axis Depth of the section Maximum compressive stress at the section ANSWER DOWNLOAD EXAMIANS APP
Theory of Structures For beams of uniform strength, if depth is constant, Width b 3 M Width b M 2 Width b M Width b 1/M Width b 3 M Width b M 2 Width b M Width b 1/M ANSWER DOWNLOAD EXAMIANS APP
Theory of Structures Slenderness ratio of a long column, is Length of column divided by least radius of gyration Area of cross-section divided by radius of gyration Area of cross-section divided by least radius of gyration Radius of gyration divided by area of cross-section Length of column divided by least radius of gyration Area of cross-section divided by radius of gyration Area of cross-section divided by least radius of gyration Radius of gyration divided by area of cross-section ANSWER DOWNLOAD EXAMIANS APP
Theory of Structures Principal planes are subjected to Normal stresses only Tangential stresses only Normal stresses as well as tangential stresses None of these Normal stresses only Tangential stresses only Normal stresses as well as tangential stresses None of these ANSWER DOWNLOAD EXAMIANS APP
EXAMIANS