Theory of Structures The stiffness of the close coil helical spring is d4N/8D3n 8D3N/d4n 4D3N/d4n d4N/4D3n d4N/8D3n 8D3N/d4n 4D3N/d4n d4N/4D3n ANSWER DOWNLOAD EXAMIANS APP
Theory of Structures The moment of inertia of a triangular section (height h, base b) about its base, is bh³/12 b²h/12 b³h/12 bh²/12 bh³/12 b²h/12 b³h/12 bh²/12 ANSWER DOWNLOAD EXAMIANS APP
Theory of Structures If a concrete column 200 × 200 mm in cross-section is reinforced with four steel bars of 1200 mm² total cross-sectional area. Calculate the safe load for the column if permissible stress in concrete is 5 N/mm² and Es is 15 Ec 264 MN 274 MN 294 MN 284 MN 264 MN 274 MN 294 MN 284 MN ANSWER DOWNLOAD EXAMIANS APP
Theory of Structures A simply supported rolled steel joist 8 m long carries a uniformly distributed load over it span so that the maximum bending stress is 75 N/mm². If the slope at the ends is 0.005 radian and the value of E = 0.2 × 106 N/mm², the depth of the joist, is 200 mm 300 mm 250 mm 400 mm 200 mm 300 mm 250 mm 400 mm ANSWER DOWNLOAD EXAMIANS APP
Theory of Structures A bar L metre long and having its area of cross-section A, is subjected to a gradually applied tensile load W. The strain energy stored in the bar is W²L/AE WL/2AE W²L/2AE WL/AE W²L/AE WL/2AE W²L/2AE WL/AE ANSWER DOWNLOAD EXAMIANS APP
Theory of Structures If E, N, K and 1/m are modulus of elasticity, modulus of rigidity. Bulk modulus and Poisson ratio of the material, the following relationship holds good All of these E = 2N (1 + 1/m) (3/2)K (1 – 2/m) = N (1 + 1/m) E = 3K (1 – 2/m) All of these E = 2N (1 + 1/m) (3/2)K (1 – 2/m) = N (1 + 1/m) E = 3K (1 – 2/m) ANSWER DOWNLOAD EXAMIANS APP
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