Theory of Structures The stiffness of the close coil helical spring is 4D3N/d4n d4N/4D3n 8D3N/d4n d4N/8D3n 4D3N/d4n d4N/4D3n 8D3N/d4n d4N/8D3n ANSWER DOWNLOAD EXAMIANS APP
Theory of Structures Stress may be expressed in Newtons Per metre square (N/m2) Per centimetre square (N/cm²) None of these Per millimetre square (N/mm²) Per metre square (N/m2) Per centimetre square (N/cm²) None of these Per millimetre square (N/mm²) ANSWER DOWNLOAD EXAMIANS APP
Theory of Structures A steel plate d × b is sandwiched rigidly between two timber joists each D × B/2 in section. The steel will be (where Young’s modulus of steel is m times that of the timber). BD² + mbd³)/4D] BD² + mbd²)/4D] BD² + mbd²)/6D] BD³ + mbd³)/6D] BD² + mbd³)/4D] BD² + mbd²)/4D] BD² + mbd²)/6D] BD³ + mbd³)/6D] ANSWER DOWNLOAD EXAMIANS APP
Theory of Structures In case of principal axes of a section Difference of moment inertia is zero Product of moment of inertia is zero None of these Sum of moment of inertia is zero Difference of moment inertia is zero Product of moment of inertia is zero None of these Sum of moment of inertia is zero ANSWER DOWNLOAD EXAMIANS APP
Theory of Structures Stress may be defined as None of these Force per unit area Force per unit length Force per unit volume None of these Force per unit area Force per unit length Force per unit volume ANSWER DOWNLOAD EXAMIANS APP
Theory of Structures If Q is load factor, S is shape factor and F is factor of safety in elastic design, the following: Q = S × F Q = S + F Q = S – F Q = F – S Q = S × F Q = S + F Q = S – F Q = F – S ANSWER DOWNLOAD EXAMIANS APP
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