Theory of Structures The area of the core of a column of cross sectional area A, is (1/18) A (1/3) A (1/6) A (1/12) A (1/18) A (1/3) A (1/6) A (1/12) A ANSWER DOWNLOAD EXAMIANS APP
Theory of Structures a uniform circular bar of diameter d and length , which extends by an The deflection of amount under a tensile pull , when it carries the same load at its mid-span, is ee²l/3d² el/2d el²/3d² e²l²/3d² ee²l/3d² el/2d el²/3d² e²l²/3d² ANSWER DOWNLOAD EXAMIANS APP
Theory of Structures For calculating the allowable stress of long columns σ0 = σy/n [1 - a (1/r)²]is the empirical formula, known as Perry Parabolic formula Rankine Straight line formula Perry Parabolic formula Rankine Straight line formula ANSWER DOWNLOAD EXAMIANS APP
Theory of Structures The ratio of the maximum deflections of a simply supported beam with a central load W and of a cantilever of same length and with a load W at its free end, is 1/8 1/16 1/12 1/10 1/8 1/16 1/12 1/10 ANSWER DOWNLOAD EXAMIANS APP
Theory of Structures A steel bar 20 mm in diameter simply-supported at its ends over a total span of 40 cm carries a load at its centre. If the maximum stress induced in the bar is limited to N/mm², the bending strain energy stored in the bar, is 411 N mm 711 N mm 611 N mm 511 N mm 411 N mm 711 N mm 611 N mm 511 N mm ANSWER DOWNLOAD EXAMIANS APP
Theory of Structures Slenderness ratio of a long column, is Area of cross-section divided by radius of gyration Radius of gyration divided by area of cross-section Area of cross-section divided by least radius of gyration Length of column divided by least radius of gyration Area of cross-section divided by radius of gyration Radius of gyration divided by area of cross-section Area of cross-section divided by least radius of gyration Length of column divided by least radius of gyration ANSWER DOWNLOAD EXAMIANS APP
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