MGVCL Exam Paper (30-07-2021 Shift 2) A single phase 240 V, 1 kW heater is connected across single phase 240 V, 50 Hz supply through an SCR. For firing angle delay of 90˚, calculate the power absorbed in the heater element. 250 W 225 W 275 W 300 W 250 W 225 W 275 W 300 W ANSWER EXPLANATION DOWNLOAD EXAMIANS APP Resistance of heater, R = V²/PR = 57.6 ohmRMS value of voltage through controlled SCR = (Vm/2π)*(1 + cosα)= 120 VPower absorb by heater = Vrms²/R= 120²/57.6= 250 W
MGVCL Exam Paper (30-07-2021 Shift 2) If all the devices are connected to a central hub, then the topology is called Star Topology Bus Topology Tree Topology Tree Topology Star Topology Bus Topology Tree Topology Tree Topology ANSWER DOWNLOAD EXAMIANS APP
MGVCL Exam Paper (30-07-2021 Shift 2) Find the word which is correctly spelt from the given options. Maximum Wrinkel Absurrd Sentimant Maximum Wrinkel Absurrd Sentimant ANSWER DOWNLOAD EXAMIANS APP
MGVCL Exam Paper (30-07-2021 Shift 2) હુ ગીત ગાઈશ' ને કર્મણીમાં ફેરવો. ગીતને હુ જ ગાઇશ હુ ગીતને ગાઈશ ગીતને હુ ગાઈશ મારાથી ગીત ગવાશે ગીતને હુ જ ગાઇશ હુ ગીતને ગાઈશ ગીતને હુ ગાઈશ મારાથી ગીત ગવાશે ANSWER DOWNLOAD EXAMIANS APP
MGVCL Exam Paper (30-07-2021 Shift 2) A short-shunt dc compound generator supplies 50 A at 300 V. If the shunt field resistance, series field resistance and armature resistance are 30 Ω, 0.03Ω, and 0.05 Ω respectively, determine the e.m.f. generated. 302.5 V 308.5 V 306.5 V 304.5 V 302.5 V 308.5 V 306.5 V 304.5 V ANSWER EXPLANATION DOWNLOAD EXAMIANS APP Here,Vt = 300 VRse = 0.03 Ω, Rsh = 30 Ω, Ra = 0.05 ΩI_L = 50 AVsh = V + I_L*Rse = 300 + 50*0.03 = 301.5 VIsh = Vsh/Rsh = 301.5/30 = 10.05 AIa = Ish + I_L = 60.05 AEg = Vt + I_L*Rse + IaRaEg = 300 + 50*0.03 + 60.05*0.05 = 304.5025 V
MGVCL Exam Paper (30-07-2021 Shift 2) સોહેલ ખાન : મલાયકા અરોર :: સૈફ અલી ખાન : ?? કિરણ ખેર માધુરી દિક્ષિત અમૃતા સિંહ પરવીન બાબી કિરણ ખેર માધુરી દિક્ષિત અમૃતા સિંહ પરવીન બાબી ANSWER DOWNLOAD EXAMIANS APP
EXAMIANS