Theory of Structures A simply supported beam which carries a uniformly distributed load has two equal overhangs. To have maximum B.M. produced in the beam least possible, the ratio of the length of the overhang to the total length of the beam, is 0.307 0.207 0.407 0.508 0.307 0.207 0.407 0.508 ANSWER DOWNLOAD EXAMIANS APP
Theory of Structures A shaft is subjected to bending moment M and a torque T simultaneously. The ratio of the maximum bending stress to maximum shear stress developed in the shaft, is 2T/M 2M/ T T/M M/T 2T/M 2M/ T T/M M/T ANSWER DOWNLOAD EXAMIANS APP
Theory of Structures A simply supported uniform rectangular bar breadth b, depth d and length L carries an isolated load W at its mid-span. The same bar experiences an extension e under same tensile load. The ratio of the maximum deflection to the elongation, is L/d L/2d (L/3d)² (L/2d)² L/d L/2d (L/3d)² (L/2d)² ANSWER DOWNLOAD EXAMIANS APP
Theory of Structures The ratio of the length and depth of a simply supported rectangular beam which experiences maximum bending stress equal to tensile stress, due to same load at its mid span, is 1/2 1/4 2/3 1/3 1/2 1/4 2/3 1/3 ANSWER DOWNLOAD EXAMIANS APP
Theory of Structures A simply supported beam carries varying load from zero at one end and w at the other end. If the length of the beam is a, the maximum bending moment will be wa/27 w²a wa²/27 wa² wa/27 w²a wa²/27 wa² ANSWER DOWNLOAD EXAMIANS APP
Theory of Structures Y are the bending moment, moment of inertia, radius of curvature, modulus of If M, I, R, E, F, and elasticity stress and the depth of the neutral axis at section, then M/I = R/E = F/Y I/M = R/E = F/Y M/I = E/R = F/Y M/I = E/R = Y/F M/I = R/E = F/Y I/M = R/E = F/Y M/I = E/R = F/Y M/I = E/R = Y/F ANSWER DOWNLOAD EXAMIANS APP
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