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Alligation or Mixture problems

Alligation or Mixture problems
A jar contains a blend of a fruit juice and water in the ratio 5 : x. When 1 litre of water is added to 4 litres of the blend the ratio of fruit juice to water becomes 1 : 1. What is the value of x?

1
2
4
3

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Alligation or Mixture problems
2/3 of a milk-water mixture was milk. There was 21 lit of the mixture. If 4 lit of water is added to it, the % of milk in the new mixture will be:

56
11
44
14

ANSWER EXPLANATION DOWNLOAD EXAMIANS APP

Let the amount of juice and water in original mixture '4x' litre and '3x' litre respectively. According to given data, 4x/3x+6 =8/7 28x=24x+48 28x?24x=48 4x = 48 x = 12 Amount of juice = 4x = 4×12 = 48 litre.

Alligation or Mixture problems
In the 75 litres of mixture of milk and water, the ratio of milk and water is 4:1. The quantity of water required to make the ratio of milk and water 3:1 is

3 litres
4 litres
1 litre
5 litres

ANSWER EXPLANATION DOWNLOAD EXAMIANS APP

Total quantity of mixture = 75 litre Milk  :  Water  =  4  :  1                                    3       :       1

Alligation or Mixture problems
A merchant has 1000 kg of sugar, part of which he sells at 8% profit and the rest at 18% profit. He gains 14% on the whole. The quantity sold at 18% profit is:

560 kg
640 kg
600 kg
400 kg

ANSWER EXPLANATION DOWNLOAD EXAMIANS APP

By the rule of alligation, we have: Profit on 1st part Profit on 2nd part 8% Mean Profit 14% 18% 4 6 Ration of 1st and 2nd parts = 4 : 6 = 2 : 3 ∴ Quantity of 2nd kind = ❨ 3 x 1000 ❩kg = 600 kg.

Alligation or Mixture problems
A jar full of whisky contains 40 % of alcohol. A part of this whisky is replaced by another containing 19 % alcohol and now the percentage of alcohol was found to be 26. The quantity of whisky replaced is ?

3 5
2 5
2 3
1 3

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Alligation or Mixture problems
If 4 kg of an alloy made of 1/4th iron and rest is mixed with 6 kg of another alloy made of 2/3rd iron and rest tin, find the ratio of iron to tin in the resultant mixture.

1 : 1
3 : 2
2 : 1
1 : 2

ANSWER EXPLANATION DOWNLOAD EXAMIANS APP

Total quantity of iron = 4 (1 / 4) + 6 (2 / 3) = 1 + 4 = 5 kg. Total quantity of tin = (4 + 6) ? 5 = 5 kg. In the resultant mixture, iron : tin = 5 : 5 or 1 : 1

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