A fault occurring at the terminals of an unloaded synchronous generator operating at its rated voltage has resulted in the following values of currents and voltages. IR0 = j 2.37 pu IR1 = -j 3.05 pu IR2 = j 0.68 pu VR0 = VR1 = VR2 = 0.237 pu. Which of the following faults has occurred?

Power Systems
A fault occurring at the terminals of an unloaded synchronous generator operating at its rated voltage has resulted in the following values of currents and voltages. IR0 = j 2.37 pu IR1 = -j 3.05 pu IR2 = j 0.68 pu VR0 = VR1 = VR2 = 0.237 pu. Which of the following faults has occurred?

LG

LL

LLL

LLG

LG

LL

LLL

LLG

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Power Systems
Breaking current is a ------------------ value?

any of the above

maximum

RMS

average

any of the above

maximum

RMS

average

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If the penalty factor of a plant is unity, its incremental transmission loss is

-1

1

None of these

0

-1

1

None of these

0

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A 3 - ÃŽÂ¦, 33 kV oil circuit breaker is rated 1200 A, 2000 MVA, 3 s. The symmetrical breaking current is

35 kA.

104.8 kA.

3600 A.

1200 A.

35 kA.

104.8 kA.

3600 A.

1200 A.

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A 100 MVA alternator operating at full load at 50 Hz. H = 4 MWsec/MVA, Td = 0.5 sec. One of the transmission line is tripped. So that output of generator is reduced to 70 MW. Find the frequency deviation during this time?

0.92

-0.92

-0.56

0.56

0.92

-0.92

-0.56

0.56

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Mercury is choice with steam in binary vapor cycle because

relative low vaporization pressure.

higher critical temperature and pressure.

higher saturation temperature than other fluids.

all of above.

relative low vaporization pressure.

higher critical temperature and pressure.

higher saturation temperature than other fluids.

all of above.

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Power Systems

Power Systems Breaking current is a ------------------ value?

Power Systems If the penalty factor of a plant is unity, its incremental transmission loss is

Power Systems A 3 - ÃŽÂ¦, 33 kV oil circuit breaker is rated 1200 A, 2000 MVA, 3 s. The symmetrical breaking current is

Power Systems A 100 MVA alternator operating at full load at 50 Hz. H = 4 MWsec/MVA, Td = 0.5 sec. One of the transmission line is tripped. So that output of generator is reduced to 70 MW. Find the frequency deviation during this time?

Power Systems Mercury is choice with steam in binary vapor cycle because

Power Systems
Breaking current is a ------------------ value?

Power Systems
If the penalty factor of a plant is unity, its incremental transmission loss is

Power Systems
A 3 - ÃŽÂ¦, 33 kV oil circuit breaker is rated 1200 A, 2000 MVA, 3 s. The symmetrical breaking current is

Power Systems
A 100 MVA alternator operating at full load at 50 Hz. H = 4 MWsec/MVA, Td = 0.5 sec. One of the transmission line is tripped. So that output of generator is reduced to 70 MW. Find the frequency deviation during this time?

Power Systems
Mercury is choice with steam in binary vapor cycle because