Heat and Mass Transfer
A composite slab has two layers of different materials with thermal conductivities k₁ and k₂. If each layer has the same thickness, then the equivalent thermal conductivity of the slab will be

k₁ k₂
(k₁ + k₂)/ k₁ k₂
(k₁ + k₂)
2 k₁ k₂/ (k₁ + k₂)

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