Theory of Structures A body is said to be in equilibrium if None of these It moves vertically It moves horizontally It rotates about its C.G. None of these It moves vertically It moves horizontally It rotates about its C.G. ANSWER DOWNLOAD EXAMIANS APP
Theory of Structures A steel plate d × b is sandwiched rigidly between two timber joists each D × B/2 in section. The steel will be (where Young’s modulus of steel is m times that of the timber). BD² + mbd³)/4D] BD² + mbd²)/4D] BD³ + mbd³)/6D] BD² + mbd²)/6D] BD² + mbd³)/4D] BD² + mbd²)/4D] BD³ + mbd³)/6D] BD² + mbd²)/6D] ANSWER DOWNLOAD EXAMIANS APP
Theory of Structures For calculating the allowable stress of long columns σ0 = σy/n [1 - a (1/r)²]is the empirical formula, known as Perry Rankine Straight line formula Parabolic formula Perry Rankine Straight line formula Parabolic formula ANSWER DOWNLOAD EXAMIANS APP
Theory of Structures An isolated load W is acting at a distance a from the left hand support, of a three hinged arch of span 2l and rise h hinged at the crown, the horizontal reaction at the support, is 2W/ha 2h/Wa Wa/2h Wa/h 2W/ha 2h/Wa Wa/2h Wa/h ANSWER DOWNLOAD EXAMIANS APP
Theory of Structures A lift of weight W is lifted by a rope with an acceleration f. If the area of cross-section of the rope is A, the stress in the rope is [W (1 + f/ G)]/ A [W (2 + g/f)]/A (1 – g/f)/A [W (2 + f/G)]/A [W (1 + f/ G)]/ A [W (2 + g/f)]/A (1 – g/f)/A [W (2 + f/G)]/A ANSWER DOWNLOAD EXAMIANS APP
Theory of Structures A truss containing j joints and m members, will be a simple truss if m = 2j – 3 j = 2m – 3 m = 3j – 2 j = 3m – 2 m = 2j – 3 j = 2m – 3 m = 3j – 2 j = 3m – 2 ANSWER DOWNLOAD EXAMIANS APP
EXAMIANS