Electrical Machines A 240 V dc series motor takes 40 A when giving its rated output at 1500 rpm. Its resistance is 0.3 Ω. The value of resistance which must be added to obtain rated torque at 1000 rpm is 2.2 Ω 6 Ω 1.9 Ω 5.7 Ω 2.2 Ω 6 Ω 1.9 Ω 5.7 Ω ANSWER DOWNLOAD EXAMIANS APP
Electrical Machines A bipolar dc machine with interpoles has a main-pole flux of ф per pole and an interpole flux of Фᵢ per pole. The yoke of the machine is devide into four quadrants by the main-pole axis and The commutation axis. The flux-distribution in the quadrants will be ½ ( ф - фᵢ ) in all the four quadrants ½ ( ф + фᵢ ) in two diametrically opposite quadrants and ½ ( ф - фᵢ ) in the remaining two Quadrants ½ ( ф + фᵢ ) in two adjacent quadrants and ½ ( ф - фᵢ ) in the remaining two quadrants ½ ( ф + фᵢ ) in all the four quadrants ½ ( ф - фᵢ ) in all the four quadrants ½ ( ф + фᵢ ) in two diametrically opposite quadrants and ½ ( ф - фᵢ ) in the remaining two Quadrants ½ ( ф + фᵢ ) in two adjacent quadrants and ½ ( ф - фᵢ ) in the remaining two quadrants ½ ( ф + фᵢ ) in all the four quadrants ANSWER DOWNLOAD EXAMIANS APP
Electrical Machines Torque developed in the rotor is inversely proportional to slip not dependent on the slip directly proportional to slip either of these inversely proportional to slip not dependent on the slip directly proportional to slip either of these ANSWER DOWNLOAD EXAMIANS APP
Electrical Machines Centrifugal switch is absent in which of the single phase induction motor? None of these Split phase motor. Shaded pole motor. PSC (permanent split capacitor) motor. None of these Split phase motor. Shaded pole motor. PSC (permanent split capacitor) motor. ANSWER DOWNLOAD EXAMIANS APP
Electrical Machines In case of DC Shunt Motor, the speed will____ if the voltage increases, neglecting armature saturation. increase decrease. remain the same. be unpredictable. increase decrease. remain the same. be unpredictable. ANSWER DOWNLOAD EXAMIANS APP
Electrical Machines If a transformer has turns ratio K, the primary and secondary current are I1 and I2 respectively and magnetizing current and core loss component of no load current Iμ and Iw respectively, then I1 = KI2. I1 = KI2 + Iμ. I1 = KI2 + Iw + Iμ.ok I1 = KI2 + Iw. I1 = KI2. I1 = KI2 + Iμ. I1 = KI2 + Iw + Iμ.ok I1 = KI2 + Iw. ANSWER DOWNLOAD EXAMIANS APP
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