Fractions and Decimals (.896 x .752 +.896 x .248) / (.7 x .034 + .7 x.966) = ? 1.28 1.31 1.25 1.33 1.28 1.31 1.25 1.33 ANSWER EXPLANATION DOWNLOAD EXAMIANS APP Given expression = (.896 x .752 +.896 x .248) / (.7 x .034 + .7 x.966)=.[896 x (.752+.248)] / [.7 x (.034+.966)] = .(896 x 1) / ( .700 x 1)=896/700 = 1.28
Fractions and Decimals 9.75 x 9.75 - 2 x 9.75 x 5.75 + 5.75 x 5.75 = ? 18 17 16 15 18 17 16 15 ANSWER EXPLANATION DOWNLOAD EXAMIANS APP Given expression = a² -2ab + b² Where a =9.75 and b=5.75= (a-b)² = (9.75 - 5.75)² = 4²=16
Fractions and Decimals (1.04 x 1.04 + 1.04 x 0.04 + 0.04 x 0.04) / (1.04 x 1.04 x 1.04 - 0.04 x 0.04 x 0.04) = ? 1 0 3 2 1 0 3 2 ANSWER EXPLANATION DOWNLOAD EXAMIANS APP Given Expression = (1.04)² + 1.04 x 0.04 + (0.04)² / (1.04)³ - (0.04)³= (a² + ab + b²) / (a³ - b³) = (a² + ab + b²) / [(a-b) (a² + ab + b²)]= 1 / (a - b)= 1/ (1.04 - 0.04) = 1
Fractions and Decimals [12 / (0.09 of 0.3)] x 2=? 800/90 8000/9 8000/90 800/9 800/90 8000/9 8000/90 800/9 ANSWER EXPLANATION DOWNLOAD EXAMIANS APP Given expression = ( 12/ 0.027) x 2= ( 12 / 0.027) x 2 = 24000/27 = 8000/9
Fractions and Decimals The place value of 3 in 0.07359 is ? 0.03 0.0003 0.003 0.3 0.03 0.0003 0.003 0.3 ANSWER EXPLANATION DOWNLOAD EXAMIANS APP The place value of 3 in the given decimal fraction is .003 i.e. 3/1000.
Fractions and Decimals If x/y = 0.3, then (2x - y)/(2x + y) = ? 0.5 0.15 0.5 0.25 0.5 0.15 0.5 0.25 ANSWER EXPLANATION DOWNLOAD EXAMIANS APP x = 0.3y Then, (y - 2x)/(y + 2x)= y - 2(0.3y)/y + 2(0.3y)= y - 0.6y/y + 0.6y= 0.4y/1.6y= 0.4/1.6 = 0.25
EXAMIANS