Fractions and Decimals If 1.5x = 0.04y, then the value of ( (y - x) / (y+x) ) is : 71/74 65/67 73/77 61/63 71/74 65/67 73/77 61/63 ANSWER EXPLANATION DOWNLOAD EXAMIANS APP x / y = 0.04 / 1.5 = 4 / 150 = 2 / 75.= > ( (y - x) / (y+x) ) = (1 - (x / y)) / ( 1 + ( x / y)) = (1 - 2/75) / (1 + 2/75) = 73/77.
Fractions and Decimals The price of commodity X increases by 40 paise every year, while the price of commodity Y increases by 15 paise every year. If in 2001, the price of commodity X was Rs. 4.20 and that of Y was Rs. 6.3 2011 2013 2012 2014 2011 2013 2012 2014 ANSWER EXPLANATION DOWNLOAD EXAMIANS APP Suppose commodity X wil cost 40 paise more than Y after Z years.Then, (4.20 + 0.40Z) - (6.30 + 0.15Z) = 0.40 0.25Z = 0.40 + 2.10 Z= X will cost 40 paise more than Y 10 years after 2001 . i.e in 2011
Fractions and Decimals [(0.05)² + (0.41)² +(0.073)²] / [(0.005)² + (0.041)² + (0.0073)²] = ? 10000 100000 100 1000 10000 100000 100 1000 ANSWER EXPLANATION DOWNLOAD EXAMIANS APP Given expression = [(0.05)² + (0.41)² +(0.073)²] / [(0.005)² + (0.041)² + (0.0073)²] Which is in form of [(a² + b² + c²)] /[ (a/10)² + (b/10)² + (c/10)²] = 100 x (a² + b² + c²) / (a²+b²+c²) = 100
Fractions and Decimals (.125 + .027) / (.5 x .5 - 1.5 + .09) = ? 8 80 800 0.8 8 80 800 0.8 ANSWER EXPLANATION DOWNLOAD EXAMIANS APP Given expression = [(0.5)³ + (0.3)³] / [(0.5)² - 0.5 x 0.3 + (0.3)²]= [a³ + b³] / [a² - ab + b²]=[(a + b)(a² - ab + b²)]/ [a² -ab + b²]= a+b = 0.5 + 0.3 = 0.8
Fractions and Decimals Two times of the third of three consecutive even integers is three times of the first. Then the second integer is 7 4 10 1 7 4 10 1 ANSWER EXPLANATION DOWNLOAD EXAMIANS APP Let the consecutive three integers be X, X + 2 and X + 4Then, 2(X + 4) = 3XX = 8Now X + 2 = 10The required second integer is 10
Fractions and Decimals If 144 / 0.144 = 14.4 / x, then the value of x is: 1.44 14.4 0.0144 0.144 1.44 14.4 0.0144 0.144 ANSWER EXPLANATION DOWNLOAD EXAMIANS APP 144 / 0.144 = 14.4 / x144 x 1000 / 144 = 14.4 / x x =14.4 / 1000 = 0.0144
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