Let X and Y are given fractions.Given that, fraction X is thrice the fraction Y;i.e., X = 3Y ...(1)And their product = X x Y = 25/12Sub. eqn (1) in above,(3Y)x(Y) = 25/123(Y²) = 25/12(Y²) = 25/36Y = 5/6Hence the required fraction is 5/6.
Given expression [(0.3333)/(0.2222)] x [((0.1667)(0.8333)) / ((0.6667)(0.1250))]=[(3333 / 2222)] x [((1/6) x (5/6)) / ((2/3) x (125/1000))]=[(3/2) x (1/6) x (5/6) x (3/2) x 8]=5 / 2=2.50
Let the weight of vesel = x kg Then, 1/4 of volume of water = (5.25 - x)kg Full volume of water = (16.5 - x)∴ 4(5.25 - x) = (16.5 - x)⇒ 21 - 4x = 16.5 - x ⇒ 21 - 16.5 = 3x ∴ x = 4.5/3 = 1.5 kg
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