Suppose commodity X wil cost 40 paise more than Y after Z years.Then, (4.20 + 0.40Z) - (6.30 + 0.15Z) = 0.40 0.25Z = 0.40 + 2.10 Z= X will cost 40 paise more than Y 10 years after 2001 . i.e in 2011
Let the worth of total property be Rs.XWe have to find 3/5 of X.Given that, 5/6 th of the property = Rs.976500i.e., 5/6 x X = 976500X = 976500 x 6/5And, 3/5 of X = 3/5 x 976500 x 6/5 = 18 x 39060 = 703080Hence the answer is Rs. 703080
Let the fraction be N.Then, N / (13/14) - (13/14) x N = 3/65⇒ 14N/13 - 13N/14 = 3/65⇒ (196N - 169N)/182 = 3/65⇒ 27N/182 = 3/65∴ N = (3 x 182) / (27 x 65) = 14/45So, correct answer will be (13/14) x (14/45) = 13/45
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