Time required for service before overhauling = 2/3h = 40 min in 45 days and time required for service after overhauling =2/3h= 40 min in 60 days Now,LCM of 45 and 60 = 180 days time required for service before overhauling is 180 days = 40 x 4 = 160 min and time required for service before overhauling is 180 days =40 x 3 = 120 min ∴ fraction of time saved = 160 - 120/160 =40/160 = 1/4
Let the weight of vesel = x kg Then, 1/4 of volume of water = (5.25 - x)kg Full volume of water = (16.5 - x)∴ 4(5.25 - x) = (16.5 - x)⇒ 21 - 4x = 16.5 - x ⇒ 21 - 16.5 = 3x ∴ x = 4.5/3 = 1.5 kg
EXAMIANS