Let man's salary be Rs. NMoney spend on food =N/7Money spends on clothing = (N - N/7) x 1/2 = (6N/7) x (1/2) =3N/7Money spend on entertainment = (N - N/7 - 3N/7)/3 = (7N - 4N)/7 = N/7Now, money left =600⇒ N - N/7 - 3N/7 - N/7 = 600⇒ 7N - 5N/7 = 600⇒ N = 600 x 7/2 = Rs. 2100∴ Money spend on entertainment = 1/7 x 2100 = Rs. 300
We have to find X such that 4/5 < X < 6/7Converting each fraction into decimal form, we get:4/5 = 0.86/7 = 0.85We have to find the fraction which is greater than 0.8 and less than 0.85.Now,2/3 = 0.663/4 = 0.755/6 = 0.8310/11 = 0.91Clearly, 0.83 lies between 0.8 and 0.85.Required fraction is 5/6
Let the worth of total property be Rs.XWe have to find 3/5 of X.Given that, 5/6 th of the property = Rs.976500i.e., 5/6 x X = 976500X = 976500 x 6/5And, 3/5 of X = 3/5 x 976500 x 6/5 = 18 x 39060 = 703080Hence the answer is Rs. 703080