Fractions and Decimals (.125 + .027) / (.5 x .5 - 1.5 + .09) = ? 80 0.8 800 8 80 0.8 800 8 ANSWER EXPLANATION DOWNLOAD EXAMIANS APP Given expression = [(0.5)³ + (0.3)³] / [(0.5)² - 0.5 x 0.3 + (0.3)²]= [a³ + b³] / [a² - ab + b²]=[(a + b)(a² - ab + b²)]/ [a² -ab + b²]= a+b = 0.5 + 0.3 = 0.8
Fractions and Decimals If √0.05 x 0.5 x a = 0.5 x 0.05 x √b, then a/b = ? .0025 25 .025 .00025 .0025 25 .025 .00025 ANSWER EXPLANATION DOWNLOAD EXAMIANS APP Given expression = √0.5 x .5 x a = .5 x .05 x √ b⇒ √.025 x a = 0.25 x ⇒ b⇒ 0.025a = 0.25 x .025 x b∴ a/b = (.025 x .025) /.025 = .025
Fractions and Decimals 16.7 + 12.38 - ? =10.09 18.99 16.99 20.99 14.99 18.99 16.99 20.99 14.99 ANSWER EXPLANATION DOWNLOAD EXAMIANS APP Let 16.7 + 12.38 - x =10.09∴ x = 16.7 + 12.38 - 10.09 = 18.99
Fractions and Decimals 999.99 + 25.012 = ? - 174.469 14 56 116 215 14 56 116 215 ANSWER EXPLANATION DOWNLOAD EXAMIANS APP ? = (999.99)/25.012 + 174.469 = (1000/25) + 174.469= (40 + 174.469) = 214.469 = 215
Fractions and Decimals If 3 is added to the denominator of a fraction, it becomes 1/3 and if 4 be added to its numerator, It becomes 3/4, then fraction is ? 5/12 1/16 3/20 None of these 5/12 1/16 3/20 None of these ANSWER EXPLANATION DOWNLOAD EXAMIANS APP Let the required fraction be p/q∵ p / (q + 3) = 1/3⇒ 3p - q = 3 ...(i)and, (p + 4) / q = 3/4 ⇒ 4p - 3q = -16 ...(ii)Solving these equations, we get p = 5, q = 12∴ Required fraction = 5/12
Fractions and Decimals If 1.5x = 0.04y, then the value of ( (y - x) / (y+x) ) is : 71/74 65/67 61/63 73/77 71/74 65/67 61/63 73/77 ANSWER EXPLANATION DOWNLOAD EXAMIANS APP x / y = 0.04 / 1.5 = 4 / 150 = 2 / 75.= > ( (y - x) / (y+x) ) = (1 - (x / y)) / ( 1 + ( x / y)) = (1 - 2/75) / (1 + 2/75) = 73/77.
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