Fractions and Decimals (.125 + .027) / (.5 x .5 - 1.5 + .09) = ? 80 8 0.8 800 80 8 0.8 800 ANSWER EXPLANATION DOWNLOAD EXAMIANS APP Given expression = [(0.5)³ + (0.3)³] / [(0.5)² - 0.5 x 0.3 + (0.3)²]= [a³ + b³] / [a² - ab + b²]=[(a + b)(a² - ab + b²)]/ [a² -ab + b²]= a+b = 0.5 + 0.3 = 0.8
Fractions and Decimals If 5/6 of a property worth be Rs.976500 then the value of 3/5 of the property is: None of these Rs. 803080 Rs. 903080 Rs. 703080 None of these Rs. 803080 Rs. 903080 Rs. 703080 ANSWER EXPLANATION DOWNLOAD EXAMIANS APP Let the worth of total property be Rs.XWe have to find 3/5 of X.Given that, 5/6 th of the property = Rs.976500i.e., 5/6 x X = 976500X = 976500 x 6/5And, 3/5 of X = 3/5 x 976500 x 6/5 = 18 x 39060 = 703080Hence the answer is Rs. 703080
Fractions and Decimals Evaluate : [(2.39)² - (1.61)²] / [2.39 - 1.61] 6 2 3 4 6 2 3 4 ANSWER EXPLANATION DOWNLOAD EXAMIANS APP Given Expression=(a² - b²) / (a - b)=[(a + b)(a - b)] / (a - b)= (a + b)= (2.39 + 1.61)= 4
Fractions and Decimals If the numerator of a fraction is increased by 2 and the denominator is increased by 1, the fraction because 5/8 and if the numerator of the same fraction is increased by 3 and the denominator is incr 2/7 1/7 3/7 4/7 2/7 1/7 3/7 4/7 ANSWER EXPLANATION DOWNLOAD EXAMIANS APP Let the original fraction be p/q Then, (p + 2) / (q + 1) = 5/8⇒ 8p - 5q = 11 .....(i)Again (p + 3) / (q + 1) = 3/4⇒ 4p - 3q = 9 ...(ii)Solving equations , (i) and (ii), we get ,p = 3 and q = 7∴ Fraction = 3/7
Fractions and Decimals If √15 = 3.88, the value of √5/3 is ? 1.29 12.9 1290 129 1.29 12.9 1290 129 ANSWER EXPLANATION DOWNLOAD EXAMIANS APP √5/3 = √15/9= √15/3= 3.88/3 = 1.29
Fractions and Decimals [(3.537 - .948)² + (3.537 + .948)²] / [(3.537)² + (.948)²] = ? 3 0 1 2 3 0 1 2 ANSWER EXPLANATION DOWNLOAD EXAMIANS APP Given expression = [(3.537 - .948)² + (3.537 + .948)²] / [(3.537)² + (.948)²] = [(a - b)² + (a + b)²] / (a²+ b²) (Where a = 3.537 and b = 0.948)= 2(a² +b²) / (a² +b²) = 2
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