Waste Water Engineering 3.0 ml of raw sewage is diluted to 300 ml. The D.O. concentration of the diluted sample at the beginning of the test was 8 mg/l. After 5 day-incubation at 20°C, the D.O. concentration was 5 mg/l. The BOD of raw sewerage is 100 mg/l 400 mg/l 200 mg/l 300 mg/l 100 mg/l 400 mg/l 200 mg/l 300 mg/l ANSWER DOWNLOAD EXAMIANS APP
Waste Water Engineering hydraulically equivalent, the relationship which holds good, is D2/3 = 4 b2/3 D3/2 = 4 b3/2 D3/8 = 4 b3/8 D8/3 = 4 b8/3 D2/3 = 4 b2/3 D3/2 = 4 b3/2 D3/8 = 4 b3/8 D8/3 = 4 b8/3 ANSWER DOWNLOAD EXAMIANS APP
Waste Water Engineering No treatment of the sewage is given if dilution factor is Between 150 to 200 Less than 150 Between 200 to 300 More than 500 Between 150 to 200 Less than 150 Between 200 to 300 More than 500 ANSWER DOWNLOAD EXAMIANS APP
Waste Water Engineering The width of a rectangular sewer is twice its depth while discharging 1.5 m/sec. The width of the sewer is 1.36 m 0.88 m 0.68 m 1.76 m 1.36 m 0.88 m 0.68 m 1.76 m ANSWER DOWNLOAD EXAMIANS APP
Waste Water Engineering The settling velocity of a spherical particle of diameter less than 0.1 mm as per Stock’s law, is Vs = 218 (Gs – Gw)d² [(3T + 70)/100] Vs = 418 (Gs – Gw)d² [(3T + 70)/100] Vs = 218 (Gs – Gw)d [(3T + 70)/100] Vs = 418 (Gs – Gw) d [(3T + 70)/100] Vs = 218 (Gs – Gw)d² [(3T + 70)/100] Vs = 418 (Gs – Gw)d² [(3T + 70)/100] Vs = 218 (Gs – Gw)d [(3T + 70)/100] Vs = 418 (Gs – Gw) d [(3T + 70)/100] ANSWER DOWNLOAD EXAMIANS APP
Waste Water Engineering Bio-chemical oxygen demand (BOD) for the first 20 days in generally referred to All of these Carbonaceous demand Initial demand First stage demand All of these Carbonaceous demand Initial demand First stage demand ANSWER DOWNLOAD EXAMIANS APP
EXAMIANS