Structural Analysis Which of the following is not the displacement method? Column analogy method Kani's method Equilibrium method Moment distribution method Column analogy method Kani's method Equilibrium method Moment distribution method ANSWER DOWNLOAD EXAMIANS APP
Structural Analysis Muller Breslau’s principle for obtaining influence lines is applicable to i) trusses ii) statically determinate beams and frames iii) statically indeterminate structures, the material of which is elastic and follows Hooke’s law iv) any statically indeterminate structure The correct answer is (i) and (ii) (i), (ii) and (iv) (i), (ii) and (iii) only (i) (i) and (ii) (i), (ii) and (iv) (i), (ii) and (iii) only (i) ANSWER DOWNLOAD EXAMIANS APP
Structural Analysis A rigid-jointed plane frame is stable and statically determinate if (where m is number of members, r is reaction components and j is number of joints) (m + r) = 3j (m + r) = 2j (3m + r) = 3j (m + 3r) = 3j (m + r) = 3j (m + r) = 2j (3m + r) = 3j (m + 3r) = 3j ANSWER DOWNLOAD EXAMIANS APP
Structural Analysis When a uniformly distributed load, longer than the span of the girder, moves from left to right, then the maximum bending moment at mid section of span occurs when the uniformly distributed load occupies Less than the left half span Whole of left half span Whole span More than the left half span Less than the left half span Whole of left half span Whole span More than the left half span ANSWER DOWNLOAD EXAMIANS APP
Structural Analysis The degree of static indeterminacy of a pin-jointed space frame is given by (where m is number of unknown member forces, r is unknown reaction components and j is number of joints) m + r – 3j m + r – 2j 3m + r – 3j m + r + 3j m + r – 3j m + r – 2j 3m + r – 3j m + r + 3j ANSWER DOWNLOAD EXAMIANS APP
Structural Analysis The fixed support in a real beam becomes in the conjugate beam a Fixed support Hinged support Roller support Free end Fixed support Hinged support Roller support Free end ANSWER DOWNLOAD EXAMIANS APP
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