Engineering Thermodynamics Which of the following is a reversible non-flow process? Hyperbolic process Isobaric process Isochoric process All of these Hyperbolic process Isobaric process Isochoric process All of these ANSWER DOWNLOAD EXAMIANS APP
Engineering Thermodynamics Mond gas is obtained by Carbonisation of bituminous coal Partial combustion of coal, coke, anthracite coal or charcoal in a mixed air steam blast Passing air and a large amount of steam over waste coal at about 650°C Passing steam over incandescent coke Carbonisation of bituminous coal Partial combustion of coal, coke, anthracite coal or charcoal in a mixed air steam blast Passing air and a large amount of steam over waste coal at about 650°C Passing steam over incandescent coke ANSWER DOWNLOAD EXAMIANS APP
Engineering Thermodynamics The heat absorbed or rejected by the working substance is given by (where ds = Increase or decrease of entropy, T = Absolute temperature, and dQ = Heat absorbed or rejected) δQ = T.ds None of the listed here δQ = T/ds dQ = ds/T δQ = T.ds None of the listed here δQ = T/ds dQ = ds/T ANSWER DOWNLOAD EXAMIANS APP
Engineering Thermodynamics In an irreversible process, there is a No loss of heat No gain of heat Loss of heat Gain of heat No loss of heat No gain of heat Loss of heat Gain of heat ANSWER DOWNLOAD EXAMIANS APP
Engineering Thermodynamics One kg of ethylene (C2H4) requires 2 kg of oxygen and produces 22/7 kg of carbon dioxide and ___ kg of water or steam. 11/4 11/7 9/7 7/4 11/4 11/7 9/7 7/4 ANSWER DOWNLOAD EXAMIANS APP
Engineering Thermodynamics If a system after undergoing a series of processes, returns to the initial state then Process is executed in closed system cycle Process is thermodynamically in equilibrium Sum of heat and work transfer will be zero Its entropy will change due to irreversibility Process is executed in closed system cycle Process is thermodynamically in equilibrium Sum of heat and work transfer will be zero Its entropy will change due to irreversibility ANSWER DOWNLOAD EXAMIANS APP
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