Engineering Thermodynamics Characteristic gas constant of a gas is equal to Cp /Cv Cv /Cp Cp - Cv Cp + Cv Cp /Cv Cv /Cp Cp - Cv Cp + Cv ANSWER DOWNLOAD EXAMIANS APP
Engineering Thermodynamics The value of the product of molecular weight and the gas characteristic constant for all the gases in M.K.S. unit is 848 kgfm/mol °K 427 kgfm/mol °K 8314 kgfm/mol °K 29.27 kgfm/mol °K 848 kgfm/mol °K 427 kgfm/mol °K 8314 kgfm/mol °K 29.27 kgfm/mol °K ANSWER DOWNLOAD EXAMIANS APP
Engineering Thermodynamics Relation between cp and cv is given by (where cp = Specific heat at constant pressure, cv = Specific heat at constant volume, γ = cp/cv, known as adiabatic index, and R = Gas constant) cv/ cp =R cp - cv = R cv = R/ γ-1 Both (B) and (C) cv/ cp =R cp - cv = R cv = R/ γ-1 Both (B) and (C) ANSWER DOWNLOAD EXAMIANS APP
Engineering Thermodynamics The main cause for the irreversibility is Mechanical and fluid friction Heat transfer with a finite temperature difference All of these Unrestricted expansion Mechanical and fluid friction Heat transfer with a finite temperature difference All of these Unrestricted expansion ANSWER DOWNLOAD EXAMIANS APP
Engineering Thermodynamics The amount of heat generated per kg of fuel is known as Lower calorific value Heat energy Calorific value Higher calorific value Lower calorific value Heat energy Calorific value Higher calorific value ANSWER DOWNLOAD EXAMIANS APP
Engineering Thermodynamics The ideal efficiency of a Brayton cycle with regeneration, with increase in pressure ratio will Remain unchanged Decrease Increase/decrease depending on application Increase Remain unchanged Decrease Increase/decrease depending on application Increase ANSWER DOWNLOAD EXAMIANS APP
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