Chemical Engineering Thermodynamics Which of the following equations is obtained on combining 1st and 2nd law of thermodynamics, for a system of constant mass? DQ = CvdT + PdV DE = Tds - PdV DQ = CpdT + Vdp Tds = dE - PdV DQ = CvdT + PdV DE = Tds - PdV DQ = CpdT + Vdp Tds = dE - PdV ANSWER DOWNLOAD EXAMIANS APP
Chemical Engineering Thermodynamics The number of degrees of freedom for an azeotropic mixture in a two component vapour-liquid equilibria is/are One Three Zero Two One Three Zero Two ANSWER DOWNLOAD EXAMIANS APP
Chemical Engineering Thermodynamics Equation which relates pressure, volume and temperature of a gas is called the Equation of state Gibbs Duhem equation None of these Ideal gas equation Equation of state Gibbs Duhem equation None of these Ideal gas equation ANSWER DOWNLOAD EXAMIANS APP
Chemical Engineering Thermodynamics Claussius-Clayperon equation gives accurate result, when the Vapour pressure is relatively low and the temperature does not vary over wide limits Vapour obeys the ideal gas law and the latent heat of vaporisation is constant Volume in the liquid state is negligible compared with that in the vapour state All of these Vapour pressure is relatively low and the temperature does not vary over wide limits Vapour obeys the ideal gas law and the latent heat of vaporisation is constant Volume in the liquid state is negligible compared with that in the vapour state All of these ANSWER DOWNLOAD EXAMIANS APP
Chemical Engineering Thermodynamics A gas has a volume of 27.3 c.c. at 0°C. Its volume at 10°C (if pressure remains unchanged) will be __________ c.c. 28.3 283 273 2.73 28.3 283 273 2.73 ANSWER DOWNLOAD EXAMIANS APP
Chemical Engineering Thermodynamics Law of corresponding states says that No gas can be liquified above the critical temperature, howsoever high the pressure may be , two different gases behave similarly, if their reduced properties (i.e. P, V and T) are same The surface of separation (i. e. the meniscus) between liquid and vapour phase disappears at the critical temperature The molar heat of energy of gas at constant volume should be nearly constant (about 3 calories) No gas can be liquified above the critical temperature, howsoever high the pressure may be , two different gases behave similarly, if their reduced properties (i.e. P, V and T) are same The surface of separation (i. e. the meniscus) between liquid and vapour phase disappears at the critical temperature The molar heat of energy of gas at constant volume should be nearly constant (about 3 calories) ANSWER DOWNLOAD EXAMIANS APP
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