Machine Design When the belt is transmitting maximum power, the belt speed should be(Where, m = mass of belt per meter (kg/m) and Pmax = maximum permissible tension in belt (N)) √(Pmax / 3m) √(3m /Pmax) √(Pmax / 2m) √(Pmax / m) √(Pmax / 3m) √(3m /Pmax) √(Pmax / 2m) √(Pmax / m) ANSWER DOWNLOAD EXAMIANS APP
Machine Design The rated life of a bearing varies Inversely as fourth power of load Inversely as square of load Inversely as cube of load Directly as load Inversely as fourth power of load Inversely as square of load Inversely as cube of load Directly as load ANSWER DOWNLOAD EXAMIANS APP
Machine Design A sliding bearing which can support steady loads without any relative motion between the journal and the bearing, is called Boundary lubricated bearing Hydrostatic lubricated bearing Zero film bearing Hydrodynamic lubricated bearing Boundary lubricated bearing Hydrostatic lubricated bearing Zero film bearing Hydrodynamic lubricated bearing ANSWER DOWNLOAD EXAMIANS APP
Machine Design Two shafts of the same length and material are joined in series. If the ratio of their diameters is 2, then the ratio of their angles of twist will be 8 16 2 4 8 16 2 4 ANSWER DOWNLOAD EXAMIANS APP
Machine Design Antifriction bearings are Hydrodynamic bearings None of these Sleeve bearings Thin lubricated bearings Hydrodynamic bearings None of these Sleeve bearings Thin lubricated bearings ANSWER DOWNLOAD EXAMIANS APP
Machine Design The ratio of belt tensions (p1/p2) considering centrifugal force in flat belt is given by Where m = mass of belt per meter (kg/m) v = belt velocity (m/s) f = coefficient of friction a = angle of wrap (radians) P1 / P2 = e–ᶠα (P1 - mv²)/ (P2 - mv²) = eᶠα (P1 - mv²)/ (P2 - mv²) = e–ᶠα P1 / P2 = eᶠα P1 / P2 = e–ᶠα (P1 - mv²)/ (P2 - mv²) = eᶠα (P1 - mv²)/ (P2 - mv²) = e–ᶠα P1 / P2 = eᶠα ANSWER DOWNLOAD EXAMIANS APP
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