Control Systems When deriving the transfer function of linear element initial conditions are taken into account but the element is assumed to be not loaded. initial conditions are assumed to be zero and the element is assumed to be not loaded. both initial conditions and loading are taken into account. initial conditions are assumed to be zero but loading is taken into account. initial conditions are taken into account but the element is assumed to be not loaded. initial conditions are assumed to be zero and the element is assumed to be not loaded. both initial conditions and loading are taken into account. initial conditions are assumed to be zero but loading is taken into account. ANSWER DOWNLOAD EXAMIANS APP
Control Systems The open loop transfer function for unity feedback system is given by Find the steady state error for a ramp input of magnitude 10? 2 5 0 infinite 2 5 0 infinite ANSWER DOWNLOAD EXAMIANS APP
Control Systems The low frequency and high frequency asymptotes of Bode magnitude plot are respectively -60dB/decade and -40dB/decade. What is the type of the system? TYPE III TYPE 0 TYPE II TYPE I TYPE III TYPE 0 TYPE II TYPE I ANSWER DOWNLOAD EXAMIANS APP
Control Systems Which of the following statements is/are true? both 1 and 2 nether 1 nor 2 Centroid may not be a part of root locus Centroid may be a part of root locus both 1 and 2 nether 1 nor 2 Centroid may not be a part of root locus Centroid may be a part of root locus ANSWER DOWNLOAD EXAMIANS APP
Control Systems A second order control system is defined by the following equation: 4 d²c(t)/dt² + 8 dc(t)/dt + 16 c(t) = 16 u(t) The damping ratio and natural frequency for this system are respectively 0.25 and 2 rad/s 0.50 and 2 rad/s 0.50 and 4 rad/s 0.25 and 4 rad/s 0.25 and 2 rad/s 0.50 and 2 rad/s 0.50 and 4 rad/s 0.25 and 4 rad/s ANSWER DOWNLOAD EXAMIANS APP
Control Systems The impulse response of an initally relaxed linear system is e-2tu(t). To produce a response of te-2tu(t), the input must be equal to e-2tu(t). e-tu(t). 2e-tu(t). (0.5)e-2tu(t). e-2tu(t). e-tu(t). 2e-tu(t). (0.5)e-2tu(t). ANSWER DOWNLOAD EXAMIANS APP
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